将Python列表拆分为更小的子字符串
我试图将一个列表分成两个子字符串,然后像字典中的键、值那样附加它们 我尝试的方法是将列表拆分为更小的子字符串,然后将索引0处的项作为键追加,将索引1作为值追加到字典中 例如 输入测试.txt将Python列表拆分为更小的子字符串,python,string,dictionary,Python,String,Dictionary,我试图将一个列表分成两个子字符串,然后像字典中的键、值那样附加它们 我尝试的方法是将列表拆分为更小的子字符串,然后将索引0处的项作为键追加,将索引1作为值追加到字典中 例如 输入测试.txt Writing Fast Tests Against Enterprise Rails 60min Overdoing it in Python 45min {'Writing Fast Tests Against Enterprise Rails': 60, 'Overdoing it
Writing Fast Tests Against Enterprise Rails 60min
Overdoing it in Python 45min
{'Writing Fast Tests Against Enterprise Rails': 60,
'Overdoing it in Python': 45}
预期产出
Writing Fast Tests Against Enterprise Rails 60min
Overdoing it in Python 45min
{'Writing Fast Tests Against Enterprise Rails': 60,
'Overdoing it in Python': 45}
到目前为止,我的方法是将列表分割成更小的子字符串
d = {}
lines = [line.strip() for line in open('test.txt')]
for line in lines:
print(line.split(maxsplit=1))
上面的代码生成以下输出
['Writing', 'Fast Tests Against Enterprise Rails 60min']
['Overdoing', 'it in Python 45min']
如何分割列表,以便将名称和时间分割成子字符串,然后将其附加到dict
谢谢谢谢@Ashwini,我得到了正确的输出。这很简单
d = {}
lines = [line.strip() for line in open('test.txt')]
for line in lines:
title, minutes = line.rsplit(maxsplit=1)
d[title] = int(minutes[:-3])
print(d)