如何在Python csv编写器中将单引号替换为双引号？

我一直在尝试使用python输出csv文件。没有引号和数字，工作正常。例如：

Automation Specialist I,"[(Automation Specialist I, Data Coordiator)]",0.01,0.0
Community Outreach Specialist,"[(Community Outreach Specialist, Librarian)]",0.01,0.0
Research Assistant III,"[(Research Assistant III, Senior Quality Engineer)]",0.01,0.0
Cost Accountant,"[(Cost Accountant, Structural Engineer)]",0.01,0.0
Data Coordiator,"[(Data Coordiator, Technical Writer), (Data Coordiator, Automation Specialist I)]",0.02,0.01

代码：

输出：

24,"[(24, 31), (24, 64)]",0.02,0.04
25,"[(25, 77)]",0.01,0.0
26,"[(26, 49)]",0.01,0.0
27,"[(27, 75), (27, 79)]",0.02,0.02
20,"[(20, 9), (20, 84), (20, 40)]",0.03,0.03
21,"[(21, 77), (21, 64)]",0.02,0.02

我需要能够输入也字符串数据。例如：

Automation Specialist I,"[(Automation Specialist I, Data Coordiator)]",0.01,0.0
Community Outreach Specialist,"[(Community Outreach Specialist, Librarian)]",0.01,0.0
Research Assistant III,"[(Research Assistant III, Senior Quality Engineer)]",0.01,0.0
Cost Accountant,"[(Cost Accountant, Structural Engineer)]",0.01,0.0
Data Coordiator,"[(Data Coordiator, Technical Writer), (Data Coordiator, Automation Specialist I)]",0.02,0.01

但是，我需要一个引用值，以便在前端处理它。像这样：

Automation Specialist I,"[("Automation Specialist I", "Data Coordiator")]",0.01,0.0
Community Outreach Specialist,"[("Community Outreach Specialist", "Librarian")]",0.01,0.0
Research Assistant III,"[("Research Assistant III", "Senior Quality Engineer")]",0.01,0.0
Cost Accountant,"[("Cost Accountant", "Structural Engineer")]",0.01,0.0
Data Coordiator,"[("Data Coordiator", "Technical Writer"), ("Data Coordiator", "Automation Specialist I")]",0.02,0.01

所以我使用了下面的代码：

csv_out.writerow([n, str(edges).replace("'",'"'), round(centrality[n],2), round(betweeness[n],2)])

if(is_number(n) == True):
    edges_w = str(edges).replace("'","")
else:
    edges_w = str(edges).replace("'",'"')

然而，结果是：

有关数字：

24,"[(""24"", ""31""), (""24"", ""64"")]",0.02,0.04
25,"[(""25"", ""77"")]",0.01,0.0
26,"[(""26"", ""49"")]",0.01,0.0

对于字符串：

Automation Specialist I,"[(""Automation Specialist I"", ""Data Coordiator"")]",0.01,0.0
Community Outreach Specialist,"[(""Community Outreach Specialist"", ""Librarian")]"",0.01,0.0

我还尝试用撇号替换掉掉引号（在列表之外），但没有成功。我也尝试使用下面的代码，但它给出了与上面相同的结果

str(edges).replace("'",'"').replace('""','"')

我应该怎么做才能得到我想要的结果？ 我计划在以后过滤输入的类型，以便仅在字符串为时应用该技术。因为如果它是一个数字，理想输出就是第一个例子。当我使用最后一个时，我的前端代码处理文本和数字。但当我使用第一个例子时，它不适用于文本，只适用于数字

你能帮帮我吗？ 如何将撇号替换为引号？

---

非常感谢。

尝试用反斜杠避开双引号。e、 g

str(edges).replace("'","\"")

---

我最终使用了以下代码：

csv_out.writerow([n, str(edges).replace("'",'"'), round(centrality[n],2), round(betweeness[n],2)])

if(is_number(n) == True):
    edges_w = str(edges).replace("'","")
else:
    edges_w = str(edges).replace("'",'"')

---

我使用了一个函数来检查它是否是一个数字，然后根据这个函数的返回值替换str。我已经考虑过@Stein comments来使用此解决方案。

应该能满足您的需求。您不应该尝试自己修改CSV文件-格式看起来很简单，但实际上要正确修改是相当棘手的。（csv_out对象的定义是相关的，把它放到问题中会对你有好处。）如果你不尝试替换任何东西，你能告诉我们这条线是什么样子吗？我想看看未格式化的文本是什么样子。。。此外，我对这个str（edges）感到困惑。替换（“，”）。替换（“，”））为什么要执行“，”以及“，”和“…”…为什么要使用不同的格式？写“[（“自动化专家I”，“数据协调器”）有什么错"? 在原始CSV格式中，引号字符应该加倍。用一个像样的CSV解析器（如Excel）读取此CSV将生成字符串[（“自动化专家I”，“数据协调器”）]，这似乎适合您的前端。这与Jaqueline所做的完全相同，只是风格问题，python似乎更喜欢Jaqueline的风格而不是您的：输入

“\”“Python提示符上的，Python将其称为“代码>”“/CODE”>如果在字符串式撇号的中间有“代码>”/代码>引用。