在Python中如何从字符串中的特定位置(而不是通过索引)删除字符
所以我有这个代码:在Python中如何从字符串中的特定位置(而不是通过索引)删除字符,python,python-3.x,Python,Python 3.x,所以我有这个代码: def myprogram(): import string import random import getpass inputpasswd = getpass.getpass("Password: ") passwd = ("I<3StackOverflow") if passwd == inputpasswd: qwerty = input("Type something: ") def add_str(lst): _letter
def myprogram():
import string
import random
import getpass
inputpasswd = getpass.getpass("Password: ")
passwd = ("I<3StackOverflow")
if passwd == inputpasswd:
qwerty = input("Type something: ")
def add_str(lst):
_letters = ("1","2","3","4","5","6","7","8","9","0","q","w","e","r","t","z","u","i","o","p","a","s","d","f","g","h","j","k","l","y","x","c","v","b","n","m","!","#","$","%","&","/","(",")","=","?","*","+","_","-",";"," ")
return [''.join(random.sample(set(_letters), 1)) + letter + ''.join(random.sample(set(_letters), 1))for letter in lst]
print(''.join(add_str(qwerty)))
input("")
else:
print("Wrong password")
input("")
def myprogram():
导入字符串
随机输入
导入getpass
inputpasswd=getpass.getpass(“密码:”)
passwd=(“我这对你有用吗?”
s="1a23a45a6"
print(s[1::3]) # aaa
这对你有用吗
s="1a23a45a6"
print(s[1::3]) # aaa
这样做:initial\u str=random\u str[1:-1:3]
,其中random\u str是带有垃圾的字符串这样做:initial\u str=random\u str[1:-1:3]
,其中random\u str是带有垃圾的字符串我不知道中的“aaaaaaaaaaaaaaa”
是“有意义的文本”“还有,这个标题与你的问题有什么关系?是一些有用的就寝时间理论……我不认为“aaaaaaa”
会是“有意义的文本”。还有,这个标题与你的问题有什么关系?是一些有用的就寝时间理论。。。