Python字典（/w值是不同长度的列表）到数据帧

我有一本这样的字典。这些值是不同长度的列表

{'New England': ['connecticut',
  'maine',
  'massachusetts',
  'new hampshire',
  'rhode island',
  'vermont'],
 'Mideast': ['delaware',
  'district of columbia',
  'maryland',
  'new jersey',
  'new york',
  'pennsylvania'],
 'Great Lakes': ['illinois', 'indiana', 'michigan', 'ohio', 'wisconsin'],
 'Plains': ['iowa',
  'kansas',
  'minnesota',
  'missouri',
  'nebraska',
  'north dakota',
  'south dakota'],
 'Southeast': ['alabama',
  'arkansas',
  'florida',
  'georgia',
  'kentucky',
  'louisiana',
  'mississippi',
  'north carolina',
  'south carolina',
  'tennessee',
  'virginia',
  'west virginia'],
 'Southwest': ['arizona', 'new mexico', 'oklahoma', 'texas'],
 'Rocky Mountain': ['colorado', 'idaho', 'montana', 'utah', 'wyoming'],
 'Far West': ['alaska',
  'california',
  'hawaii',
  'nevada',
  'oregon',
  'washington']}

我想把它做成一个有两列的熊猫数据框，如下所示

+-------------+--------------+
|region       | state        |
+-------------|--------------+
|New England  | connecticut  |
+-------------|--------------+
|New England  | maine        |
+-------------|--------------+
|New England  | massachusetts|
+-------------|--------------+
|New England  | new hampshire|
+-------------|--------------+
| Mideast     | new york     |
+-------------|--------------+
| Mideast     | new jersey   |
+-------------|--------------+

我怎样才能做到呢

我有一列美国州，我想把它们分类为区域，所以我需要一个数据框架来合并

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非常感谢

使用

列表理解

将传递给

DataFrame

构造函数的元组列表的键中列表的值展平：

df = pd.DataFrame([(k, x) for k, v in d.items() for x in v],
                  columns=['region','state'])
print (df.head(10))
        region                 state
0  New England           connecticut
1  New England                 maine
2  New England         massachusetts
3  New England         new hampshire
4  New England          rhode island
5  New England               vermont
6      Mideast              delaware
7      Mideast  district of columbia
8      Mideast              maryland
9      Mideast            new jersey
    

编辑：循环解决方案：

out = []
for k, v in d.items():
    for x in v:
        out.append((k, x))
        
df = pd.DataFrame(out, columns=['region','state'])

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完美的谢谢你能把列表理解转换成for循环，这样我就能更好地理解了吗？@tainangao-当然，给我一点时间