Python 如何将字符串拆分为3组，然后相应地打印到该组？

这个问题是重复的。我知道。然而，最后一个答案是针对Python2.7的，并且在终端中使用过，我还需要将其他一些东西纳入其中

这是我的代码：

n=3 xdict={ 苯丙氨酸：[UUU，UUC]，亮氨酸：[UUA，CUU，CUC，CUA，CUG，UUG]， 异亮氨酸：[AUU，AUC，AUA]，蛋氨酸：AUG，缬氨酸：[GUU，GUC，GUA，GUG]， 丝氨酸：[UCU，UCC，UCA，UCG]，脯氨酸：[CCU，CCC，CCA，CCG]， 苏氨酸：[ACU，ACC，ACA，ACG]，丙氨酸：[GCU，GCC，GCA，GCG]， 酪氨酸：[UAU，UAC]，组氨酸：[CAU，CAC]，谷氨酰胺：[CAA，CAG]， 天冬酰胺：[AAU，AAC]，赖氨酸：[AAA，AAG]，天冬氨酸：[GAU，GAC]， 谷氨酸：[GAA，GAG]，半胱氨酸：[UGU，UGC]，Trytophan:UGG， 精氨酸：[CGU，CGC，CGA，CGG，AGG，AGA]，丝氨酸：[AGU，AGC]， 甘氨酸：[GGU，GGC，GGA，GGG] } lookup_dict={k:key for key，xdict中的值。items for k in values} a=输入您的DNA序列： 直线=a 第[i:i+n]行表示范围为0的i，lenline，n取自其他答案 printlookup_dict[行]根据其他答案编辑 我该如何操作这段代码，以便如果我输入像uuu-cuua这样的东西，它将通过将字符串拆分为3的部分来打印苯丙氨酸苯丙氨酸亮氨酸

例子

可以将一个字符分为三个字符组

n = 3

xdict = {
    "Phenylalanine": ["UUU", "UUC"],
    "Leucine": ["UUA", "CUU", "CUC", "CUA", "CUG", "UUG"],
    "Isoleucine": ["AUU", "AUC", "AUA"],
    "Methionine": "AUG",
    "Valine": ["GUU", "GUC", "GUA", "GUG"],
    "Serine": ["UCU", "UCC", "UCA", "UCG"],
    "Proline": ["CCU", "CCC", "CCA", "CCG"],
    "Threonine": ["ACU", "ACC", "ACA", "ACG"],
    "Alanine": ["GCU", "GCC", "GCA", "GCG"],
    "Tyrosine": ["UAU", "UAC"],
    "Histidine": ["CAU", "CAC"],
    "Glutamine": ["CAA", "CAG"],
    "Asparagine": ["AAU", "AAC"],
    "Lysine": ["AAA", "AAG"],
    "Asparatic Acid": ["GAU", "GAC"],
    "Glutamic Acid": ["GAA", "GAG"],
    "Cysteine": ["UGU", "UGC"],
    "Trytophan": "UGG",
    "Arginine": ["CGU", "CGC", "CGA", "CGG", "AGG", "AGA"],
    "Serine": ["AGU", "AGC"],
    "Glycine": ["GGU", "GGC", "GGA", "GGG"]
}

lookup_dict = {k: key for key, values in xdict.items() for k in values}
a = 'UUUUUCUUA'  # input("Enter your DNA sequence: ")

for k in [a[i:i + n] for i in range(0, len(a), n)]:
    print(lookup_dict[k])

可以将一个字符分为三个字符组

n = 3

xdict = {
    "Phenylalanine": ["UUU", "UUC"],
    "Leucine": ["UUA", "CUU", "CUC", "CUA", "CUG", "UUG"],
    "Isoleucine": ["AUU", "AUC", "AUA"],
    "Methionine": "AUG",
    "Valine": ["GUU", "GUC", "GUA", "GUG"],
    "Serine": ["UCU", "UCC", "UCA", "UCG"],
    "Proline": ["CCU", "CCC", "CCA", "CCG"],
    "Threonine": ["ACU", "ACC", "ACA", "ACG"],
    "Alanine": ["GCU", "GCC", "GCA", "GCG"],
    "Tyrosine": ["UAU", "UAC"],
    "Histidine": ["CAU", "CAC"],
    "Glutamine": ["CAA", "CAG"],
    "Asparagine": ["AAU", "AAC"],
    "Lysine": ["AAA", "AAG"],
    "Asparatic Acid": ["GAU", "GAC"],
    "Glutamic Acid": ["GAA", "GAG"],
    "Cysteine": ["UGU", "UGC"],
    "Trytophan": "UGG",
    "Arginine": ["CGU", "CGC", "CGA", "CGG", "AGG", "AGA"],
    "Serine": ["AGU", "AGC"],
    "Glycine": ["GGU", "GGC", "GGA", "GGG"]
}

lookup_dict = {k: key for key, values in xdict.items() for k in values}
a = 'UUUUUCUUA'  # input("Enter your DNA sequence: ")

for k in [a[i:i + n] for i in range(0, len(a), n)]:
    print(lookup_dict[k])

列表理解要求循环中有[]

[line[i:i+n] for i in range(0, len(line), n)]  

是每个长度为3的字符串的列表。将代码中的最后两行替换为以下内容：

for s in [line[i:i+n] for i in range(0, len(line), n)]:
     print(lookup_dict[s])

列表理解要求循环中有[]

[line[i:i+n] for i in range(0, len(line), n)]  

是每个长度为3的字符串的列表。将代码中的最后两行替换为以下内容：

for s in [line[i:i+n] for i in range(0, len(line), n)]:
     print(lookup_dict[s])

您可以将列表的内部xdict更改为集合并使用交叉点

xdict = {
    "Phenylalanine": {"UUU", "UUC"},
    "Leucine": {"UUA", "CUU", "CUC", "CUA", "CUG", "UUG"},
    "Isoleucine": {"AUU", "AUC", "AUA"},
    "Methionine": {"AUG"},
    "Valine": {"GUU", "GUC", "GUA", "GUG"},
    "Serine": {"UCU", "UCC", "UCA", "UCG"},
    "Proline": {"CCU", "CCC", "CCA", "CCG"},
    "Threonine": {"ACU", "ACC", "ACA", "ACG"},
    "Alanine": {"GCU", "GCC", "GCA", "GCG"},
    "Tyrosine": {"UAU", "UAC"},
    "Histidine": {"CAU", "CAC"},
    "Glutamine": {"CAA", "CAG"},
    "Asparagine": {"AAU", "AAC"},
    "Lysine": {"AAA", "AAG"},
    "Asparatic Acid": {"GAU", "GAC"},
    "Glutamic Acid": {"GAA", "GAG"},
    "Cysteine": {"UGU", "UGC"},
    "Trytophan": {"UGG"},
    "Arginine": {"CGU", "CGC", "CGA", "CGG", "AGG", "AGA"},
    "Serine": {"AGU", "AGC"},
    "Glycine": {"GGU", "GGC", "GGA", "GGG"}
}

使用从文本换行到拆分输入的换行

from textwrap import wrap

a = set(wrap("UUUUUAUUC", 3)) # {'UUA', 'UUC', 'UUU'}
print([key for key, value in xdict.items() for _ in value & a])

您可以将列表的内部xdict更改为集合并使用交叉点

xdict = {
    "Phenylalanine": {"UUU", "UUC"},
    "Leucine": {"UUA", "CUU", "CUC", "CUA", "CUG", "UUG"},
    "Isoleucine": {"AUU", "AUC", "AUA"},
    "Methionine": {"AUG"},
    "Valine": {"GUU", "GUC", "GUA", "GUG"},
    "Serine": {"UCU", "UCC", "UCA", "UCG"},
    "Proline": {"CCU", "CCC", "CCA", "CCG"},
    "Threonine": {"ACU", "ACC", "ACA", "ACG"},
    "Alanine": {"GCU", "GCC", "GCA", "GCG"},
    "Tyrosine": {"UAU", "UAC"},
    "Histidine": {"CAU", "CAC"},
    "Glutamine": {"CAA", "CAG"},
    "Asparagine": {"AAU", "AAC"},
    "Lysine": {"AAA", "AAG"},
    "Asparatic Acid": {"GAU", "GAC"},
    "Glutamic Acid": {"GAA", "GAG"},
    "Cysteine": {"UGU", "UGC"},
    "Trytophan": {"UGG"},
    "Arginine": {"CGU", "CGC", "CGA", "CGG", "AGG", "AGA"},
    "Serine": {"AGU", "AGC"},
    "Glycine": {"GGU", "GGC", "GGA", "GGG"}
}

使用从文本换行到拆分输入的换行

from textwrap import wrap

a = set(wrap("UUUUUAUUC", 3)) # {'UUA', 'UUC', 'UUU'}
print([key for key, value in xdict.items() for _ in value & a])

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你能给我们更多的输出例子吗？在0，lenline，n范围内，i的行[i:i+n]没有任何作用。您没有将结果列表保存在任何位置-例如，通过将其存储在变量中：新变量=行[i:i+n]表示范围0、lenline、nCan中的i，您能给我们更多输出示例吗？行[i:i+n]表示范围0、lenline、n中的i，它没有做任何事情。您没有将结果列表保存在任何位置-例如，将其存储在变量中：new_variable=line[i:i+n]表示范围0、lenline、n中的i