无法使用python feedparser存储媒体标题

无法使用python feedparser存储媒体标题,python,rss,media,rss-reader,feedparser,Python,Rss,Media,Rss Reader,Feedparser,我尝试使用feedparser存储网站的提要,但问题是xml格式的每个媒体内容都有一个媒体标题,但在使用python feedparser库进行解析时,我无法获得媒体标题 <media:thumbnail url="https://thechive.files.wordpress.com/2017/02/oscarlead.jpg?quality=85&amp;strip=info&amp;w=500" /> <media:content url

我尝试使用feedparser存储网站的提要,但问题是xml格式的每个媒体内容都有一个媒体标题,但在使用python feedparser库进行解析时,我无法获得媒体标题

<media:thumbnail url="https://thechive.files.wordpress.com/2017/02/oscarlead.jpg?quality=85&amp;strip=info&amp;w=500" />
        <media:content url="http://2.gravatar.com/avatar/b51c0c859ad69354d498cd688e281907?s=50&amp;d=http%3A%2F%2F2.gravatar.com%2Favatar%2Fad516503a11cd5ca435acc9bb6523536%3Fs%3D50&amp;r=X" medium="image">
        <media:category>author</media:category>
    </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-2.gif" medium="image">
        <media:title>nicoleslenderman</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-29.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet9</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-28.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet8</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-27.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet7</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-26.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet6</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-25.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet5</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-21.gif" medium="image">
        <media:title>oscarshighfive</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-24.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet4</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-23.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet3</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/stealoscar.gif" medium="image">
        <media:title>stealoscar</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-22.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet2</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-21.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet1</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/best-oscar-tweets-so-far-x-photos-2.jpg?quality=85&amp;strip=info" medium="image">
        <media:title>oscar-tweet0</media:title>
                </media:content>
        <media:content url="https://thechive.files.wordpress.com/2017/02/oscargif.gif" medium="image">
        <media:title>oscargif</media:title>
                </media:content>
所以在这个字典列表中,我只得到两个属性url和medium。那么如何获取标题

这是我的密码:-

    d = feedparser.parse(url_dict[item])
    total_entries = len(d.entries)

    try:
        for entry in range(0, total_entries):
            data = d.entries[entry]

            print (data)
            article_date = data.get('published', '')
            article_title = data.get('title', '')
            content = data.get('content', '')
            summary = data.get('summary', '')
            media_content = data.get('media_content')
            print media_content

最好用您编写的一些代码来回答您的问题,以便其他人能够调查可能的错误。@Hossein我已经添加了代码。据我所知,这是feedparser中的一个错误。我也有同样的问题。最好用您编写的一些代码来回答您的问题,以便其他人能够调查可能的错误。@Hossein我已经添加了代码。据我所知,这是feedparser中的一个错误。我也有同样的问题。
    d = feedparser.parse(url_dict[item])
    total_entries = len(d.entries)

    try:
        for entry in range(0, total_entries):
            data = d.entries[entry]

            print (data)
            article_date = data.get('published', '')
            article_title = data.get('title', '')
            content = data.get('content', '')
            summary = data.get('summary', '')
            media_content = data.get('media_content')
            print media_content