Python 而循环未按预期退出

您好，很抱歉问初学者的问题，但这让我挠头。我以前曾尝试在if语句中使用break语句来退出代码，但无论输入如何，都会中断。代码如下所示：

def describePet(petBreed, petName):
    print('I have a pet ' + petBreed)
    print('My ' + petBreed + '\'s name is ' + petName + '.')


while True:
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    if name or breed == 'quit':
        break
    else:
        describePet(breed, name)

print('test') 

def describePet(petBreed, petName):
    print('I have a pet ' + petBreed)
    print('My ' + petBreed + '\'s name is ' + petName + '.')


breed = None
name = None
while breed or name != 'quit':
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    describePet(breed, name)

print('test')

def describePet(petBreed, petName):
print('I have a pet ' + petBreed)
print('My ' + petBreed + '\'s name is ' + petName + '.')


while True:
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    if name == 'quit' or breed == 'quit':
        break
    else:
        describePet(breed, name)

print('test') 

我差点把它作为一个问题发布出来，但后来又重新格式化了。不过，我还是希望能以这样一种方式给出一个答案，即我能够获得所需的输出，但在输入预期的退出语句时无法中断循环。重做代码如下所示：

def describePet(petBreed, petName):
    print('I have a pet ' + petBreed)
    print('My ' + petBreed + '\'s name is ' + petName + '.')


while True:
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    if name or breed == 'quit':
        break
    else:
        describePet(breed, name)

print('test') 

def describePet(petBreed, petName):
    print('I have a pet ' + petBreed)
    print('My ' + petBreed + '\'s name is ' + petName + '.')


breed = None
name = None
while breed or name != 'quit':
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    describePet(breed, name)

print('test')

def describePet(petBreed, petName):
print('I have a pet ' + petBreed)
print('My ' + petBreed + '\'s name is ' + petName + '.')


while True:
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    if name == 'quit' or breed == 'quit':
        break
    else:
        describePet(breed, name)

print('test') 

---

如果您能让我知道，当我将字符串quit存储在任一变量中时，为什么这段代码没有退出，我们将不胜感激。谢谢大家!

在while循环中，执行以下操作：

def describePet(petBreed, petName):
    print('I have a pet ' + petBreed)
    print('My ' + petBreed + '\'s name is ' + petName + '.')


while True:
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    if name or breed == 'quit':
        break
    else:
        describePet(breed, name)

print('test') 

def describePet(petBreed, petName):
    print('I have a pet ' + petBreed)
    print('My ' + petBreed + '\'s name is ' + petName + '.')


breed = None
name = None
while breed or name != 'quit':
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    describePet(breed, name)

print('test')

def describePet(petBreed, petName):
print('I have a pet ' + petBreed)
print('My ' + petBreed + '\'s name is ' + petName + '.')


while True:
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    if name == 'quit' or breed == 'quit':
        break
    else:
        describePet(breed, name)

print('test') 

---

使用name或breed==“quit”之类的值永远不会计算为true，因为它将首先计算name或breed，而name或breed始终是一个布尔值，而这不是您所期望的值。

请尝试以下步骤以在代码中添加新的值。 1.在代码的第一部分中，按如下所示更改if条件。如果name=='quit'或breed=='quit'

def describePet(petBreed, petName):
  print('I have a pet ' + petBreed)
  print('My ' + petBreed + '\'s name is ' + petName + '.')

  while True:
    print('Type quit to exit.')
    breed = input('What is your pets breed?: ')
    name = input('What is your pets name?: ')
    if name =='quit'  or breed == 'quit':
        break
    else:
        describePet(breed, name)

然后修改while循环条件，如下所示

而繁殖“退出”或“名称！=”退出

---

如果name='quit'或breed='quit'，请更正这样的条件。while条件中存在相同的逻辑错误。while繁殖或名称！='“退出”不会像您预期的那样起作用。它会检查品种是否存在或名称是否为“退出”。啊，好的，我现在明白了。谢谢你。你可以对答案进行投票，这样对其他人也会有帮助。我有，但因为我的声誉太低，所以没有公开。