Python ValueError:以10为基数的int（）的文本无效：''；，如何使用用户输入的值作为列表中的索引

我试图教自己如何编程，从而建立一个玩家yahtzee游戏（之前没有任何经验），并已达到用户输入他希望重新掷骰子的程度

while True: 

turn1 = raw_input("Would you like to cast your first throw?")

if (turn1 == "y"):

    first_roll = roll()
    print_all_5(first_roll)
    print("You have rolled a: " + " ".join(str(first_roll)))

    if (raw_input("Would you like to reroll any if your dice?") == "y"):
        print("Please input which dice you would like to reroll (first, second, third etc) with one digit")
        rerolled_dice1 = raw_input("I want to reroll dice/dices number: ")
        for x in rerolled_dice1:
            first_roll[int(x) -1] = randint(1,6)
elif (turn1 == "n"):
    print("Well why even bother wasting your battery life to run these measily 106 lines of code?")
else:
    print("Respond only with 'y' for yes and 'n' for no please x_X")

我试图做的是将用户输入的值存储到列表变量rerolled_dice1中，然后对其进行迭代，将存储为str的值转换为int，并将其用作first_roll的索引，该变量保存与原始掷骰集对应的值，并将其更改为随机值号码

当我运行代码时，我得到的回溯是：

Traceback (most recent call last):
 File "C:\Python27\projects\oneplayer.py", line 110, in <module>
   first_roll[int(x) -1] = randint(1,6)
ValueError: invalid literal for int() with base 10: ''

---

你是说

int（x）

而不是

int（重新滚动的骰子1）

？你还会注意到一种模式

dice3

的作用与

dice1

和

dice2

相同

dice 5

完成dice 6所做的一切，除了

dice[1][2]=“O”

。感谢您的帮助，同时更新了回溯。你的意思是我只需要几个函数就可以写骰子了吗？情节越来越复杂了。在重新滚动的骰子1.strip（）.split（）中为x使用

：

，非常感谢；D

from random import randint 

def roll():
        dice_values = []

        for x in range (5):
            dice = randint(1,6)
            dice_values.append(dice)


        return dice_values

def create_dice():
        dice = []                  # create empty list - main dice
        for i in range(3):         #loop building a dice list containing three row sublists
            row = ["*"] * 3        #create row containing three lists each holding a str
            dice.append(row)       #append row list to dice list 
        return dice                #!! important return dice list from function


def print_dice(dice):            # prints out dice list neatly
    for row in dice:         # uses the index to access lst value in dice lst           
        print(" ".join(row)) # joins strings with space in between

def dice1 (dice): 
    dice[1][1] = "O"
    return dice


def dice2 (dice): 
    dice[0][0] = "O"
    dice[2][2] = "O"
    return dice

def dice3 (dice):
    dice[0][0] = "O"
    dice[1][1] = "O"
    dice[2][2] = "O"
    return dice


def dice4 (dice): 
    dice[0][0] = "O"
    dice[0][2] = "O"
    dice[2][0] = "O"
    dice[2][2] = "O"
    return dice

def dice5 (dice): 
    dice[0][0] = "O"
    dice[0][2] = "O"
    dice[1][1] = "O"
    dice[2][0] = "O"
    dice[2][2] = "O"
    return dice


def dice6 (dice): 

    dice[0][0] = "O"
    dice[0][2] = "O"
    dice[1][0] = "O"
    dice[1][2] = "O"
    dice[2][0] = "O"
    dice[2][2] = "O"
    return dice

def print_all_5(elist):
    print("\n")
    for x in elist:
        if x == 1:
            print(print_dice(dice1(create_dice())))
        elif x == 2:
            print(print_dice(dice2(create_dice())))
        elif x == 3:
            print(print_dice(dice3(create_dice())))
        elif x == 4:
            print(print_dice(dice4(create_dice())))
        elif x == 5:
            print(print_dice(dice5(create_dice())))
        else:
            print(print_dice(dice6(create_dice())))
    print("\n")