将用于查找集的所有分区的函数从Python转换为Ruby
我使用以下python函数递归查找集合的所有分区:将用于查找集的所有分区的函数从Python转换为Ruby,python,ruby,Python,Ruby,我使用以下python函数递归查找集合的所有分区: def partitions(set_): if not set_: yield [] return for i in xrange(2**len(set_)/2): parts = [set(), set()] for item in set_: parts[i&1].add(item) i >>
def partitions(set_):
if not set_:
yield []
return
for i in xrange(2**len(set_)/2):
parts = [set(), set()]
for item in set_:
parts[i&1].add(item)
i >>= 1
for b in partitions(parts[1]):
yield [parts[0]]+b
for p in partitions(["a", "b", "c", "d"]):
print(p)
有人能帮我把这个翻译成ruby吗?这就是我到目前为止所做的:
def partitions(set)
if not set
yield []
return
end
(0...2**set.size/2).each { |i|
parts = [Set.new, Set.new]
set.each { |item|
parts[i&1] << item
i >>= 1
}
partitions(parts[1]).each { |b|
yield [parts[0]] << b
}
}
end
p partitions([1, 2, 3, 4].to_set)
def分区(设置)
如果不设置
收益率[]
返回
结束
(0…2**set.size/2)。每个{i|
零件=[Set.new,Set.new]
设置每个{项目|
零件[i&1]>=1
}
分区(部分[1])。每个{b|
yield[parts[0]]您必须将Ruby的yield
看作是对用户定义操作的调用
def twice
yield
yield
end
twice { puts "Hello" }
因此,只要代码生成一个值,就会调用该元素的处理函数
partitions([1, 2, 3, 4].to_set) { |result|
# process result
}
此代码根本不生成列表。#!/usr/bin/ruby1.8
#!/usr/bin/ruby1.8
def partitions(set)
yield [] if set.empty?
(0 ... 2 ** set.size / 2).each do |i|
parts = [[], []]
set.each do |item|
parts[i & 1] << item
i >>= 1
end
partitions(parts[1]) do |b|
result = [parts[0]] + b
result = result.reject do |e|
e.empty?
end
yield result
end
end
end
partitions([1, 2, 3, 4]) do |e|
p e
end
# => [[1, 2, 3, 4]]
# => [[2, 3, 4], [1]]
# => [[1, 3, 4], [2]]
# => [[3, 4], [1, 2]]
# => [[3, 4], [2], [1]]
# => [[1, 2, 4], [3]]
# => [[2, 4], [1, 3]]
# => [[2, 4], [3], [1]]
# => [[1, 4], [2, 3]]
# => [[1, 4], [3], [2]]
# => [[4], [1, 2, 3]]
# => [[4], [2, 3], [1]]
# => [[4], [1, 3], [2]]
# => [[4], [3], [1, 2]]
# => [[4], [3], [2], [1]]
def分区(设置)
如果设置为空,收益率[]?
(0…2**set.size/2)。每个do | i|
零件=[],[]
设置每个do |项目|
零件[i&1]>=1
结束
分区(第[1]部分)do | b|
结果=[部分[0]]+b
结果=结果。拒绝do | e|
e、 空的?
结束
产量结果
结束
结束
结束
分区([1,2,3,4])不|
体育课
结束
# => [[1, 2, 3, 4]]
# => [[2, 3, 4], [1]]
# => [[1, 3, 4], [2]]
# => [[3, 4], [1, 2]]
# => [[3, 4], [2], [1]]
# => [[1, 2, 4], [3]]
# => [[2, 4], [1, 3]]
# => [[2, 4], [3], [1]]
# => [[1, 4], [2, 3]]
# => [[1, 4], [3], [2]]
# => [[4], [1, 2, 3]]
# => [[4], [2, 3], [1]]
# => [[4], [1, 3], [2]]
# => [[4], [3], [1, 2]]
# => [[4], [3], [2], [1]]
有什么不同:
- 警卫调用set.empty?而不是
(隐式)测试set.nil
- 打电话时,请不要打电话
分割
- 使用数组而不是集合
- 过滤空套出的数据
结果
您在哪里找到Python函数分区的?要了解相关内容,我想阅读您找到它的博客条目或章节。谢谢。