Python 如何在列表中找到最长的单词

我试过这个：

sentence = input("Sentence without punctuation: ")


lst = [sentence]
longestString = max(lst, key=len)
print(longestString)


print(len(longestString))

sentence = input("Sentence without punctuation: ")


lst = [sentence]
longestString = max(lst, key=len)
print(longestString)


print(len(longestString))

但我的输出是：

sentence = input("Sentence without punctuation: ")


lst = [sentence]
longestString = max(lst, key=len)
print(longestString)


print(len(longestString))

sentence = input("Sentence without punctuation: ")


lst = [sentence]
longestString = max(lst, key=len)
print(longestString)


print(len(longestString))

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如果你想把你的句子分解成单词，而不是这个

lst = [sentence]

你反而想要

lst = sentence.split()

---

否则，您将创建一个包含单个元素的列表，该元素是您的整个字符串。

只需将

lst=[句子]

替换为

lst=句子.split（）

您提供了代码作为输出…这是否回答了您的问题？