Python Matplotlib-未显示子批次
我想把一个普通的绘图变成一个子绘图。下面是绘图的代码,它可以工作:Python Matplotlib-未显示子批次,python,matplotlib,Python,Matplotlib,我想把一个普通的绘图变成一个子绘图。下面是绘图的代码,它可以工作: import numpy as np import pandas as pd import matplotlib.pyplot as plt from matplotlib.figure import Figure d = {'A': [1, 2, 3, 4, 5, 6], 'B': [-2.5, -1.00, .25, 1.56, .75, 1.20]} df = pd.DataFrame(data=d) x = np.
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
from matplotlib.figure import Figure
d = {'A': [1, 2, 3, 4, 5, 6], 'B': [-2.5, -1.00, .25, 1.56, .75, 1.20]}
df = pd.DataFrame(data=d)
x = np.arange(0, 999, 0.1)
y1 = -.75
y2 = .75
plt.fill_between(x, y1, y2, color='lawngreen', alpha='.6')
plt.scatter(df.A, df.B)
plt.plot(df.A, df.B)
plt.axhline(y=0, color='black')
plt.xticks(np.arange(0, 999))
plt.ylim([-4, 4])
plt.xlim([0, df.A.max() + 1])
plt.show()
然后我试着把它变成一个子地块。控制台没有抛出任何错误,只是没有显示任何绘图
fig = Figure()
ax = fig.add_subplot(111)
x = np.arange(0, 999, 0.1)
y1 = -.75
y2 = .75
ax.fill_between(x, y1, y2, color='lawngreen', alpha='.6')
ax.scatter(df.A, df.B)
ax.plot(df.A, df.B)
ax.axhline(y=0, color='black')
ax.set_xticks(np.arange(0, 999))
ax.set_ylim([-4, 4])
ax.set_xlim([0, df.A.max() + 1])
plt.show()
我做错了什么?用fig=plt.figure()
代替fig=figure()
您的代码是:
fig = plt.figure()
ax = fig.add_subplot(111)
x = np.arange(0, 999, 0.1)
y1 = -.75
y2 = .75
ax.fill_between(x, y1, y2, color='lawngreen', alpha='.6')
ax.scatter(df.A, df.B)
ax.plot(df.A, df.B)
ax.axhline(y=0, color='black')
ax.set_xticks(np.arange(0, 999))
ax.set_ylim([-4, 4])
ax.set_xlim([0, df.A.max() + 1])
plt.show()
输出: