在python中按特定顺序解析xml标记
我想按指定顺序将一些标记从xml文件加载到python中,如下所示:在python中按特定顺序解析xml标记,python,xml,parsing,Python,Xml,Parsing,我想按指定顺序将一些标记从xml文件加载到python中,如下所示: <data> <testset name="ts1" order="1" descrption="this is ts1 descrption"> <testcase name="tc1" order="1" /> <testcase name="tc2" order="2" /> </testset> <
<data>
<testset name="ts1" order="1" descrption="this is ts1 descrption">
<testcase name="tc1" order="1" />
<testcase name="tc2" order="2" />
</testset>
<testset name="ts2" order="2" descrption="this is ts2 descrption">
<testcase name="tc3" order="1" />
<testcase name="tc4" order="2" />
</testset>
</data>
我知道的方式很难看,所以请告诉我是否有更好的方式:
class TS():
def __init__(self, name, order):
self.name = name
self.order = order
import xml.etree.ElementTree as ET
def parseXML():
ts_arr = []
tree = ET.parse('test_specs.xml')
root = tree.getroot()
for testset in root.iter('testset'):
i = 0
while i<len(ts_arr):
if testset.get('order')<ts_arr[i].order:
ts_arr.append(i, TS(testset.get('name'),testset.get('order')))
break
i += 1
class TS():
定义初始化(自身、名称、顺序):
self.name=名称
self.order=order
将xml.etree.ElementTree作为ET导入
def parseXML():
ts_arr=[]
tree=ET.parse('test_specs.xml'))
root=tree.getroot()
对于root.iter('testset')中的testset:
i=0
而i则按顺序属性对测试集进行排序:
root = tree.getroot()
testsets = root.findall('testset')
for testset in sorted(testsets, key=lambda ts: int(ts.attrib['order'])):
# test sets are looped over in the order specified in the `order` attributes
testcases = testset.findall('testcase')
for testcase in sorted(testcases, key=lambda ts: int(ts.attrib['order'])):
# test cases are looped over in the order specified
精彩的。百分之百的成功。谢谢