Python 将两列数据帧转换为多索引系列

如何打开此数据帧：

In [1]: df
Out[1]:
col_name         C    P
FULL  count_x    1    5
      count_y    2    6
CALIB count_x    3    7
      count_y    4    8

在本系列中：

In [2]: s
Out[2]:    
C  FULL  count_x    1
         count_y    2
   CALIB count_x    3
         count_y    4
P  FULL  count_x    5
         count_y    6
   CALIB count_x    7
         count_y    8

Python 3，Pandas 1.1.1.

两个级别都使用：

s = df.unstack([0,1])
print (s)
C  FULL      count_x    1
             count_y    2
   CALIB     count_x    3
             count_y    4
P  FULL      count_x    5
             count_y    6
   CALIB     count_x    7
             count_y    8
dtype: int64

另一个想法与另一个过程有关，但有必要进行另一个过程，并且：

尝试新事物

out = pd.concat({x : df[x] for x in df.columns})
Out[113]: 
   col_name  col_name1
C  FULL      count_x      1
             count_y      2
   CALIB     count_x      3
             count_y      4
P  FULL      count_x      5
             count_y      6
   CALIB     count_x      7
             count_y      8
dtype: int64

---

我总是忘了拆堆栈！

out = pd.concat({x : df[x] for x in df.columns})
Out[113]: 
   col_name  col_name1
C  FULL      count_x      1
             count_y      2
   CALIB     count_x      3
             count_y      4
P  FULL      count_x      5
             count_y      6
   CALIB     count_x      7
             count_y      8
dtype: int64