Python 如何删除包含数字、特殊字符、网站url或电子邮件的整个句子？

如何删除包含数字、特殊字符、网站url或电子邮件的整个句子

示例输入选项A：

['Hi my name is blank.', 'Do it 3 times.', 'Check out this website: https://blah.com', 'I like pie.', 'My email is asdf@jkl@gmail.com.']

示例输入选项B：

['Hi my name is blank. Do it 3 times. Check out this website: https://blah.com', 'I like pie. My email is asdf@jkl@gmail.com.]

样本输出：

['Hi my name is blank.','I like pie']

当前代码：

def remove_emails(self, dataframe):
    self.log.info('Removing emails from text data')
    no_emails = dataframe.str.replace('\S*@\S*\s?', '')
    return no_emails

def remove_website_links(self, dataframe):
    self.log.info('Removing website links from text data')
    no_website_links = dataframe.str.replace('http\S+', '')
    return no_website_links

def remove_special_characters(self, dataframe):
    self.log.info('Removing special characters from text data')
    no_special_characters = dataframe.replace(r'[^A-Za-z0-9 ]+', '', regex=True)
    return no_special_characters

def remove_numbers(self, dataframe):
    self.log.info('Removing numbers from text data')
    no_numbers = dataframe.str.replace('\d+', '')
    return no_numbers

---

问题是上面的代码可以用来将不需要的字符串替换为空字符串，但是如果一个列表元素与上面给出的任何正则表达式匹配，我不知道如何删除整个列表元素。我也不希望对每一个句子摘录都多次浏览这个列表。总的来说，我正在从语料库中删除不好的句子。

您可以使用这个正则表达式检查各种情况，并拒绝匹配它的字符串

https?:|@\w+|\d

Python代码

import re

arr = ['Hi my name is blank.', 'Do it 3 times.', 'Check out this website: https://blah.com', 'I like pie', 'My email is asdf@jkl@gmail.com']

for s in arr:
 m = re.search(r'https?:|@\w+|\d',s)
 if (m):
  pass
 else:
  print(s)

结果只有你想要的句子

Hi my name is blank.
I like pie

---

您可以使用这个正则表达式检查各种情况，并拒绝匹配它的字符串

https?:|@\w+|\d

Python代码

import re

arr = ['Hi my name is blank.', 'Do it 3 times.', 'Check out this website: https://blah.com', 'I like pie', 'My email is asdf@jkl@gmail.com']

for s in arr:
 m = re.search(r'https?:|@\w+|\d',s)
 if (m):
  pass
 else:
  print(s)

结果只有你想要的句子

Hi my name is blank.
I like pie

---

那么问题出在哪里？@Alderven在问题中补充了澄清。那么问题出在哪里？@Alderven在问题中补充了澄清。