在使用Beautiful Soup的Python中使用multiple for循环

下面的代码是用于获取1项的测试

from bs4 import BeautifulSoup as bs
import requests
import pandas as pd

url = "https://www.property24.com/for-sale/woodland-hills-wildlife-estate/bloemfontein/free-state/10467/109825373"

data = requests.get(url)
soup = bs(data.content,"html.parser")

下面的代码是我们必须获得所有col-xs-6 p24_propertyOverviewKey的代码

property_overview = soup.find(class_="p24_regularListing").find(class_="p24_propertyOverview").find(class_='p24_propertyOverviewRow').find(class_='col-xs-6 p24_propertyOverviewKey').text

property_overview

Output : 'Listing Number'

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上述代码仅输出1项。并非所有的更简单地说，您可以使用

soup.select（）

（然后通过注释，您可以使用

.get_text（）

从每个标记中提取文本）

---

让BeautifulSoup做硬循环工作会更容易吗？问题是我尝试了“查找”而不是“选择”，你让我的一天变得轻松多了。然后您将如何在文本中获得此输出？添加了一个真实的答案。：）

p24_regularListing_items = soup.find_all(class_="p24_regularListing")

for p24_propertyOverview_item in p24_regularListing_items:
    p24_propertyOverview_items = p24_propertyOverview_item.find_all(class_="p24_propertyOverview")
        
    for p24_propertyOverviewRow_item in p24_propertyOverview_items:
        p24_propertyOverviewRow_items = p24_propertyOverviewRow_item.find_all(class_="p24_propertyOverviewRow")
        
        for p24_propertyOverviewKey_item in p24_propertyOverviewRow_items:
            p24_propertyOverviewKey_items = p24_propertyOverviewKey_item.find_all(class_="col-xs-6 p24_propertyOverviewKey")
        
p24_propertyOverviewKey_items

from bs4 import BeautifulSoup
import requests

resp = requests.get(
    "https://www.property24.com/for-sale/woodland-hills-wildlife-estate/bloemfontein/free-state/10467/109825373"
)
resp.raise_for_status()
soup = BeautifulSoup(resp.content, "html.parser")
texts = []
for tag in soup.select(
    # NB: this selector uses Python's implicit string concatenation
    #     to split it onto several lines.
    ".p24_regularListing "
    ".p24_propertyOverview "
    ".p24_propertyOverviewRow "
    ".p24_propertyOverviewKey"
):
    texts.append(tag.get_text())
print(texts)