Python 如何通过搜索特定关键字在列表中打印列表?
我想写一个python函数,它将通过搜索特定关键字在列表中打印列表。这是我的功能,但不起作用Python 如何通过搜索特定关键字在列表中打印列表?,python,list,Python,List,我想写一个python函数,它将通过搜索特定关键字在列表中打印列表。这是我的功能,但不起作用 user_adresses = [["John","Walker","New York","10001"],["Larry","Smith","Denver","80123"]] def search(user_adresses): alpha = str(input("What are you searching for? ")) for item in user_adress
user_adresses = [["John","Walker","New York","10001"],["Larry","Smith","Denver","80123"]]
def search(user_adresses):
alpha = str(input("What are you searching for? "))
for item in user_adresses:
print(str(item[0:])[1:-1])
程序将询问我正在搜索什么,如果我键入“John”,它将只打印带有John->“John”、“Walker”、“New York”、“10001”的列表
但用这种方式,它会让我打印所有列表。应该向函数中添加哪些内容以仅打印包含特定关键字的列表
谢谢您可以使用中的
检查列表中的成员身份。这将匹配用户地址中的所有完整单词
for user in user_adresses:
if alpha in user:
print(user)
使用
运算符中的检查输入是否在给定项中您可以非常简洁地表达这一点:
for match in (address in user_addresses if alpha in address):
print(match)
这将打印每个匹配项,其中“匹配项”是用户地址中的任何“地址”
,如果alpha
一词出现在地址中这种代码和平应该起作用。
考虑使用字典代替列表。
def search(user_addresses):
alpha = input("What are you searching for? ")
for user_address in user_addresses:
if alpha in user_address:
print(user_address)
def search(user_addresses):
alpha = input("What are you searching for? ")
for user_address in user_addresses:
if alpha in user_address:
print(user_address)