Python多处理导致整个脚本循环

看起来线程之间的多处理交换速度更快，所以我开始进行交换，但我得到了一些意想不到的结果。它会导致我的整个脚本在线程之前没有循环的情况下循环多次

代码段示例：

stuff_needs_done = true
more_stuff_needs_done =  true
print "Doing stuff"

def ThreadStuff():
  while 1 == 1:
    #do stuff here

def OtherThreadStuff():
  while 1 == 1:
    #do other stuff here

if stuff_needs_done == true:
  Thread(target=ThreadStuff).start()

if more_stuff_needs_done == true:
  Thread(target=OtherThreadStuff).start()

stuff_needs_done = true
more_stuff_needs_done = true
print "Doing stuff"


def ThreadStuff():
  while 1 == 1:
    #do stuff here

def OtherThreadStuff():
  while 1 == 1:
    #do other stuff here

if stuff_needs_done == true:
  stuffproc1= Process(target=ThreadStuff).start()

if more_stuff_needs_done == true:
  stuffproc1= Process(target=OtherThreadStuff).start()

这正是我所期望的。线程开始运行，直到停止。但是当运行很多这样的程序时，开销会更高，所以我被告知，所以我尝试切换到多处理

代码段示例：

stuff_needs_done = true
more_stuff_needs_done =  true
print "Doing stuff"

def ThreadStuff():
  while 1 == 1:
    #do stuff here

def OtherThreadStuff():
  while 1 == 1:
    #do other stuff here

if stuff_needs_done == true:
  Thread(target=ThreadStuff).start()

if more_stuff_needs_done == true:
  Thread(target=OtherThreadStuff).start()

stuff_needs_done = true
more_stuff_needs_done = true
print "Doing stuff"


def ThreadStuff():
  while 1 == 1:
    #do stuff here

def OtherThreadStuff():
  while 1 == 1:
    #do other stuff here

if stuff_needs_done == true:
  stuffproc1= Process(target=ThreadStuff).start()

if more_stuff_needs_done == true:
  stuffproc1= Process(target=OtherThreadStuff).start()

但似乎整个过程都会启动几次，所以会出现Doing stuff输出，并运行几个线程

我可以加入一些.join，但是没有循环会导致打印输出再次运行，这意味着它无处等待

我希望这只是一个语法问题，但我很难找到整个脚本循环的原因。我非常感谢任何指向正确方向的指针。

这在以下章节中提到：

主模块的安全导入

确保新的Python解释器可以安全地导入主模块，而不会造成诸如 开始一个新的过程

例如，在运行以下模块的Windows下，会出现运行时错误：

from multiprocessing import Process

def foo():
    print 'hello'

p = Process(target=foo)
p.start()

相反，应该使用if uuu name uuuuu=='uuuu main uuuuuuuu'：来保护程序的“入口点”，如下所示：

from multiprocessing import Process, freeze_support

def foo():
    print 'hello'

if __name__ == '__main__':
    freeze_support()
    p = Process(target=foo)
    p.start()

这允许新生成的Python解释器安全地导入模块，然后运行模块的foo函数

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几乎每行都有语法错误。请在你的帖子中更正它们。