Python 每次我在代码中键入elif时，它在我启动程序时显示错误

每次我在代码中键入elif时，它在我启动程序时显示错误

# This is game creating practice
import random
secretNumber = random.randint(1, 20)
print('I am thinking of a number between 1 and 20.')

# Ask the player to guess 6 times
for guessesTaken in range(1, 7):
    print('Take a guess.')
    guess = int(input())

    if guess < secretNumber:
        print('Your guess is too low.')
        elif guess > secretNumber:
            print('Your guess is to high.')
        else:
            break  # This condition is the correct guess!

if guess == secretNumber:
    print('Good job! You guessed my number in ' + str(guessesTaken) + ' guesses!)
else:
    print('Nope. The number I was thinking of was ' + str(secretNumber))

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在Python中，空格很重要

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您的elif应该与if位于同一列。

帮助您做什么？你还没有问过问题这是一个问答网站，不是一个编码教程服务。有什么错误？？？但答案是因为您的elif不在正确的缩进级别。请检查您的elif和else语句上的缩进。还要确保在猜测后关闭字符串！。由于一个简单的输入错误而关闭。您在“猜测”中缺少一个报价！谢谢。这对我很有帮助。else语句也会受到影响，不要忘记在代码末尾关闭字符串文字。