Python 检查字典是否包含true或false数据，然后返回响应

这是一个json响应，我从我的web客户端视图得到，我想检查这个列表字典是否包含数据。我如何继续？谢谢

 [
{
    "id": 41,
    "commercialOffice": false,
    "haveStoreRooms": false,
    "workFromHome": false,
    "seperateOffice": false,
    "receptionArea": false,
    "standardInsurance": false,
    "teamAudit": false,
    "auditReport": false,
    "receptionist": false,
    "qualityAssuranceTeam": false,
    "subContractor": null,
    "employeeIdentityCard": false,
    "employeeUniform": false,
    "insuranceList": "",
    "company": null
},
{
    "id": 45,
    "commercialOffice": false,
    "haveStoreRooms": false,
    "workFromHome": false,
    "seperateOffice": false,
    "receptionArea": false,
    "standardInsurance": false,
    "teamAudit": false,
    "auditReport": false,
    "receptionist": false,
    "qualityAssuranceTeam": false,
    "subContractor": null,
    "employeeIdentityCard": false,
    "employeeUniform": false,
    "insuranceList": "0",
    "company": 71
},
{
    "id": 46,
    "commercialOffice": true,
    "haveStoreRooms": true,
    "workFromHome": false,
    "seperateOffice": false,
    "receptionArea": false,
    "standardInsurance": true,
    "teamAudit": false,
    "auditReport": false,
    "receptionist": false,
    "qualityAssuranceTeam": false,
    "subContractor": null,
    "employeeIdentityCard": true,
    "employeeUniform": false,
    "insuranceList": "0",
    "company": 68
},

]

我在想这个

def (self):
   dic = {'key1': ['value1', 'value2'],
       'key2':  'value77' }
       values = dic.values()
      'value77' in [x for v in values for x in v if type(v)==list] or 
      'value77' in values

---

这取决于你所说的数据是什么意思。有录音机钥匙吗？它是给定的dict密钥吗

在Python中，空的dict是错误的，因此只要调用列表就会告诉您每个dict是否至少有一个键值对：

>>> all( [ {1:2}, {'A':'B'} ] )
True
>>> all( [ {1:2}, {'A':'B'}, {}, {3:4}] )
False

---

如果要检查每个dict中是否存在给定的键，可以将列表理解与

get

结合使用in操作符：

if b in a:

演示：

>>> a = {'foo': 1, 'bar': 2}
>>> 'foo' in a
True
>>> 'spam' in a
False

dic_3 = {'key1': ['value1', 'value2'],'key2':  '','key3':None }
for key, value in dic_3.iteritems():
    if value is None or value =='':
        print key ,"is Empty"

key3 is Empty
key2 is Empty

对于你的答案，@Eric Duminil解释的是更好的解决方案

根据您的要求更新：

>>> a = {'foo': 1, 'bar': 2}
>>> 'foo' in a
True
>>> 'spam' in a
False

dic_3 = {'key1': ['value1', 'value2'],'key2':  '','key3':None }
for key, value in dic_3.iteritems():
    if value is None or value =='':
        print key ,"is Empty"

key3 is Empty
key2 is Empty

输出：

>>> a = {'foo': 1, 'bar': 2}
>>> 'foo' in a
True
>>> 'spam' in a
False

dic_3 = {'key1': ['value1', 'value2'],'key2':  '','key3':None }
for key, value in dic_3.iteritems():
    if value is None or value =='':
        print key ,"is Empty"

key3 is Empty
key2 is Empty

---

你想查什么？请把问题贴好。。要检查dict中的数据，您可以在Operator中使用。我只想检查每个键是否包含值，然后返回一个响应。请我添加更多信息。。。是的。我已经做了。但是，它仍然不能解决我的问题。@Patco:你到底想检查什么？代码示例似乎不适合您的数据。您的dict值不是列表。请检查我的更新Answer@Eric实际上是一个json数据包。所以我想检查是否每个子类都包含数据，然后返回True或False。@PATCO:是否接受

False

或空字符串作为值？