Python 选择列中的行，其中一列中的值是另一列中值的子字符串

我在下面有一个数据框

>df = pd.DataFrame({'A':['apple','orange','grape','pear','banana'], \
                    'B':['She likes apples', 'I hate oranges', 'This is a random sentence',\
                         'This one too', 'Bananas are yellow']})

>print(df)

    A       B
0   apple   She likes apples
1   orange  I hate oranges
2   grape   This is a random sentence
3   pear    This one too
4   banana  Bananas are yellow

我正在尝试获取列B包含列A中的值的所有行

预期结果：

    A       B
0   apple   She likes apples
1   orange  I hate oranges
4   banana  Bananas are yellow

我只能使用

>df[df['B'].str.contains(df.iloc[0,0])]

    A       B
0   apple   She likes apples

如何获取所有这些行？

与将两个值转换为lower和test contains by

一起使用，并通过以下方式进行过滤：

或列出理解解决方案：

df = df[[a in b.lower() for a, b in zip(df.A, df.B)]]


df = df[[a in b.lower() for a, b in zip(df.A, df.B)]]

print (df)
        A                   B
0   apple    She likes apples
1  orange      I hate oranges
4  banana  Bananas are yellow