R基线图-无法将每个点连接到一条线

R基线图-无法将每个点连接到一条线,r,plot,base,line-plot,R,Plot,Base,Line Plot,使用“plot{base}”绘制线图时出现问题 我的数据框看起来像: month.count.success month result n percent 1 Jan Successful 93 17.71429 3 Feb Successful 934 13.84319 5 Mar Successful 3701 14.25325 7 Apr Successful 7613 15.33550 9 May Succe

使用“plot{base}”绘制线图时出现问题

我的数据框看起来像:

month.count.success

   month     result     n  percent

1    Jan Successful    93 17.71429

3    Feb Successful   934 13.84319

5    Mar Successful  3701 14.25325

7    Apr Successful  7613 15.33550

9    May Successful 14685 14.65247

11   Jun Successful 18967 14.69365

13   Jul Successful 26700 16.73656

15   Aug Successful 25006 15.07684

17   Sep Successful 23351 16.02391

19   Oct Successful 19996 14.11419

21   Nov Successful 19139 13.71018

23   Dec Successful 16669 12.76819
我想用以下方法绘制一幅图:

plot(month.count.success$month, month.count.success$percent, type = 'o') 
但是这个图不适合我,不是把每个点连接到一条线上, 它看起来像:

month.count.success

   month     result     n  percent

1    Jan Successful    93 17.71429

3    Feb Successful   934 13.84319

5    Mar Successful  3701 14.25325

7    Apr Successful  7613 15.33550

9    May Successful 14685 14.65247

11   Jun Successful 18967 14.69365

13   Jul Successful 26700 16.73656

15   Aug Successful 25006 15.07684

17   Sep Successful 23351 16.02391

19   Oct Successful 19996 14.11419

21   Nov Successful 19139 13.71018

23   Dec Successful 16669 12.76819

你能告诉我如何把每个月的成功率画成一条线吗?
提前感谢您解决此问题

我假设
month.count.success$month
是一个因子(请使用
is.factor(month.count.success$month)
)。在这种情况下,默认情况下,
plot
将创建一个箱线图,假设您只有一个值,它对应于一条水平线。用数字向量代替x,e。g<代码>绘图(1:12,month.count.success$percent,type='o')。啊,明白了,非常感谢你告诉我这个!