R基线图-无法将每个点连接到一条线
使用“plot{base}”绘制线图时出现问题 我的数据框看起来像:R基线图-无法将每个点连接到一条线,r,plot,base,line-plot,R,Plot,Base,Line Plot,使用“plot{base}”绘制线图时出现问题 我的数据框看起来像: month.count.success month result n percent 1 Jan Successful 93 17.71429 3 Feb Successful 934 13.84319 5 Mar Successful 3701 14.25325 7 Apr Successful 7613 15.33550 9 May Succe
month.count.success
month result n percent
1 Jan Successful 93 17.71429
3 Feb Successful 934 13.84319
5 Mar Successful 3701 14.25325
7 Apr Successful 7613 15.33550
9 May Successful 14685 14.65247
11 Jun Successful 18967 14.69365
13 Jul Successful 26700 16.73656
15 Aug Successful 25006 15.07684
17 Sep Successful 23351 16.02391
19 Oct Successful 19996 14.11419
21 Nov Successful 19139 13.71018
23 Dec Successful 16669 12.76819
我想用以下方法绘制一幅图:
plot(month.count.success$month, month.count.success$percent, type = 'o')
但是这个图不适合我,不是把每个点连接到一条线上,
它看起来像:
month.count.success
month result n percent
1 Jan Successful 93 17.71429
3 Feb Successful 934 13.84319
5 Mar Successful 3701 14.25325
7 Apr Successful 7613 15.33550
9 May Successful 14685 14.65247
11 Jun Successful 18967 14.69365
13 Jul Successful 26700 16.73656
15 Aug Successful 25006 15.07684
17 Sep Successful 23351 16.02391
19 Oct Successful 19996 14.11419
21 Nov Successful 19139 13.71018
23 Dec Successful 16669 12.76819
你能告诉我如何把每个月的成功率画成一条线吗?
提前感谢您解决此问题 我假设
month.count.success$month
是一个因子(请使用is.factor(month.count.success$month)
)。在这种情况下,默认情况下,plot
将创建一个箱线图,假设您只有一个值,它对应于一条水平线。用数字向量代替x,e。g<代码>绘图(1:12,month.count.success$percent,type='o')。啊,明白了,非常感谢你告诉我这个!