rpy2,copula,如何导入参数?python
我想翻译一下:rpy2,copula,如何导入参数?python,r,python-2.7,rpy2,code-translation,R,Python 2.7,Rpy2,Code Translation,我想翻译一下: library(copula) myCop.clayton <- archmCopula(family="clayton", dim =7, param=2) myMvd <- mvdc(copula=myCop.clayton, margins=c("norm", "norm"), paramMargins = list(list(mean=0.66,sd = 0.1),
library(copula)
myCop.clayton <- archmCopula(family="clayton", dim =7, param=2)
myMvd <- mvdc(copula=myCop.clayton, margins=c("norm", "norm"),
paramMargins = list(list(mean=0.66,sd = 0.1),
list(mean=0.66,sd = 0.1)))
paramMargins = list(list(mean=0.66,sd = 0.1), list(mean=0.66,sd = 0.1))
但不幸的是,在RStudio和Python解释器中生成的绘图是完全不同的。我如何翻译:
library(copula)
myCop.clayton <- archmCopula(family="clayton", dim =7, param=2)
myMvd <- mvdc(copula=myCop.clayton, margins=c("norm", "norm"),
paramMargins = list(list(mean=0.66,sd = 0.1),
list(mean=0.66,sd = 0.1)))
paramMargins = list(list(mean=0.66,sd = 0.1), list(mean=0.66,sd = 0.1))
变成Python
致意
拉法R码
库(copula)
米库普·克莱顿
ListVector([("V1", ListVector([{"mean": 0.66, "sd": 0.1}])),
("V2", ListVector([{"mean": 0.66, "sd": 0.1}]))])