R 文本数据集中的最长行
我正在寻找一种方法来查找文本文件中最长行的长度R 文本数据集中的最长行,r,text-mining,tm,R,Text Mining,Tm,我正在寻找一种方法来查找文本文件中最长行的长度 例如从代码> TM 包中考虑一个简单的数据集。< /P> install.packages("tm") library(tm) txt <- system.file("texts", "txt", package = "tm") ovid <- VCorpus(DirSource(txt, encoding = "UTF-8"), readerControl = list(language = "lat")) length(ov
例如从代码> TM 包中考虑一个简单的数据集。< /P>
install.packages("tm")
library(tm)
txt <- system.file("texts", "txt", package = "tm")
ovid <- VCorpus(DirSource(txt, encoding = "UTF-8"), readerControl =
list(language = "lat"))
length(ovid)
[1] 5
事实上,当我们去掉空白处的填充后,它是第四个最长的文本。这是怎么做的。请注意,这其中很大一部分是由于从tm(V)语料库对象中获取文本的困难,例如,以前曾多次询问过该对象
请注意,我将您关于“行”的问题解释为指五个文档,每个文档超过五行,但包含多行(每个文档长度在16到18个字符向量之间)。我希望我的解释是正确的
texts <- sapply(ovid$content, "[[", "content")
str(texts)
## List of 5
## $ : chr [1:16] " Si quis in hoc artem populo non novit amandi," " hoc legat et lecto carmine doctus amet." " arte citae veloque rates remoque moventur," " arte leves currus: arte regendus amor." ...
## $ : chr [1:17] " quas Hector sensurus erat, poscente magistro" " verberibus iussas praebuit ille manus." " Aeacidae Chiron, ego sum praeceptor Amoris:" " saevus uterque puer, natus uterque dea." ...
## $ : chr [1:17] " vera canam: coeptis, mater Amoris, ades!" " este procul, vittae tenues, insigne pudoris," " quaeque tegis medios, instita longa, pedes." " nos venerem tutam concessaque furta canemus," ...
## $ : chr [1:17] " scit bene venator, cervis ubi retia tendat," " scit bene, qua frendens valle moretur aper;" " aucupibus noti frutices; qui sustinet hamos," " novit quae multo pisce natentur aquae:" ...
## $ : chr [1:18] " mater in Aeneae constitit urbe sui." " seu caperis primis et adhuc crescentibus annis," " ante oculos veniet vera puella tuos:" " sive cupis iuvenem, iuvenes tibi mille placebunt." ...
看起来更像是这样。现在我们可以找出哪一个最长
nchar(texts)
## [1] 600 621 644 668 622
which.max(nchar(texts))
## [1] 4
which.max(nchar(ovid))
?感谢您的建议,但恐怕它没有返回正确的答案。您想要五个元素的最大长度
?即长度的max
(lappy(ovid,as.character))
?实际上,该命令返回的是列表中最长字符向量的长度,即ovid
。对象ovid是一个字符向量列表,列表的第五个元素有18个元素,其中三个是空字符串。看看lappy(ovid,as.character))
这会很清楚。@KenBenoit你是对的。现在我明白我的错误了。伙计们,我很抱歉把问题说错了。我真的很感谢你的努力。你的解释正确。这是我的错。实际上,我混淆了这五个文件,认为它们是长度为16、18 ecc的“行”。因此,问题的真正目标是组成五个文档的字符向量的长度。谢谢你让我明白。我真的很感谢你的努力,不客气。听起来这是一个值得接受的答案:-),绝对是。也有道理。它帮助我在数据挖掘领域迈出了沉重的第一步!
# need to trim leading and trailing whitespace
texts <- lapply(texts, stringi::stri_trim_both)
## texts[1]
## [[1]]
## [1] "Si quis in hoc artem populo non novit amandi," "hoc legat et lecto carmine doctus amet."
## [3] "arte citae veloque rates remoque moventur," "arte leves currus: arte regendus amor."
## [5] "" "curribus Automedon lentisque erat aptus habenis,"
## [7] "Tiphys in Haemonia puppe magister erat:" "me Venus artificem tenero praefecit Amori;"
## [9] "Tiphys et Automedon dicar Amoris ego." "ille quidem ferus est et qui mihi saepe repugnet:"
## [11] "" "sed puer est, aetas mollis et apta regi."
## [13] "Phillyrides puerum cithara perfecit Achillem," "atque animos placida contudit arte feros."
## [15] "qui totiens socios, totiens exterruit hostes," "creditur annosum pertimuisse senem."
# now paste them together to make a single character vector of the five documents
texts <- sapply(texts, paste, collapse = "\n")
str(texts)
## chr [1:5] "Si quis in hoc artem populo non novit amandi,\nhoc legat et lecto carmine doctus amet.\narte citae veloque rates remoque movent"| __truncated__ ...
cat(texts[1])
## Si quis in hoc artem populo non novit amandi,
## hoc legat et lecto carmine doctus amet.
## arte citae veloque rates remoque moventur,
## arte leves currus: arte regendus amor.
##
## curribus Automedon lentisque erat aptus habenis,
## Tiphys in Haemonia puppe magister erat:
## me Venus artificem tenero praefecit Amori;
## Tiphys et Automedon dicar Amoris ego.
## ille quidem ferus est et qui mihi saepe repugnet:
##
## sed puer est, aetas mollis et apta regi.
## Phillyrides puerum cithara perfecit Achillem,
## atque animos placida contudit arte feros.
## qui totiens socios, totiens exterruit hostes,
## creditur annosum pertimuisse senem.
nchar(texts)
## [1] 600 621 644 668 622
which.max(nchar(texts))
## [1] 4