R 如何创建具有三个参数的函数

我正在尝试创建一个函数，其中包含三个参数作为我的家庭作业，并且已经尝试了好几次，但没有成功！非常感谢您的建议或帮助：）

我已经创建了以下内容：

##### 1)
> raceIDs
[1] "GER" "SUI" "NZ2" "US1" "US2" "POR" "FRA" "AUS" "NZ1" "SWE"

##### 2)
#For each "raceIDs", there is a csv file which I have made a loop to read and created a list of data frames (assigned to the symbol "boatList")
#For example, if I select "NZ1" the output is:
> head(boatList[[9]]) #Only selected the first six lines as there is more than 30000 rows
  Boat       Date    Secs    LocalTime   SOG
1  NZ1 01:09:2013 38150.0 10:35:49.997 22.17
2  NZ1 01:09:2013 38150.2 10:35:50.197 22.19
3  NZ1 01:09:2013 38150.4 10:35:50.397 22.02
4  NZ1 01:09:2013 38150.6 10:35:50.597 21.90
5  NZ1 01:09:2013 38150.8 10:35:50.797 21.84
6  NZ1 01:09:2013 38151.0 10:35:50.997 21.95

##### 3)
# A matrix showing the race times for each raceIDs
> raceTimes
    start      finish    
GER "11:10:02" "11:35:05"
SUI "11:10:02" "11:35:22"
NZ2 "11:10:02" "11:34:12"
US1 "11:10:01" "11:33:29"
US2 "11:10:01" "11:36:05"
POR "11:10:02" "11:34:31"
FRA "11:10:02" "11:34:45"
AUS "11:10:03" "11:36:48"
NZ1 "11:10:01" "11:35:16"
SWE "11:10:03" "11:35:08"

我需要做的是，我需要计算一艘船“在比赛时”（在开始和结束时间之间）的平均速度（SOG）

基本上，我需要做一个类似的函数：

> meanRaceSpeed("NZ1", boatList, raceTimes)
[1] 18.32  

> meanRaceSpeed("US1", boatList, raceTimes)
[1] 17.23

这是我作业的最后一个问题，我完全被卡住了：(

我甚至不知道从哪里开始

---

有谁能给我一些建议或支持吗？

因为这是一个家庭作业问题，直接回答可能对任何人都没有好处

有关功能的更多信息，请参见例如

一个具有三个参数的函数示例，该函数不执行任何操作，只返回串联的参数：

myfunc <- function(first, second, third) {
return(cat(first, second, third))
}

---

myfunc我认为您不需要三个参数，因为您的三个参数是相互关联的，即当指定了一条船时，也可以指定它在
boatList
中的位置，也可以指定它的
raceTimes

我没有测试以下函数，因为模拟随机数据有点痛苦，但我相信这可能会有所帮助：

meanRaceSpeed <- function(x)  #`x` is the boat's name
 {
  start_time <- raceTimes$start[rownames(raceTimes) == x] 
  finish_time <- raceTimes$finish[rownames(raceTimes) == x]

  #which `LocalTime` is the first with `start_time`
  start_LocalTime <- min(grep(start_time, boatList[[x]]$LocalTime))
  #which `LocalTime` is the last with `finish _time`
  #(if you want the first `finish_time` change `max` with `min`)
  finish_LocalTime <- max(grep(finish_time, boatList[[x]]$LocalTime))

  #which `SOG`s contain all the `LocalTimes` between start and finish
  #take their `mean`
  mean(boatList[[x]]$SOG[start_LocalTime : finish_LocalTime])
 }

#for all boats, something like:
sapply(raceIDs, meanRaceSpeed)

meanRaceSpeed作业，因此仅提示：您可以使用“NZ1”参数提取矩阵的子集：
newmat