在likert堆叠比例条形图中显示每个类别的百分比
我是一个新手(如果这太基本了,很抱歉),我正在尝试使用“HH”包中的plot.Likert()在Likert类型的数据集中显示我的每个答案选项的百分比。在某种程度上,我使用下面的代码(我取自代码)得到了期望的结果,但问题是,如果某个特定类别没有值(=0%),那么这将与中心类别的%值冲突在likert堆叠比例条形图中显示每个类别的百分比,r,R,我是一个新手(如果这太基本了,很抱歉),我正在尝试使用“HH”包中的plot.Likert()在Likert类型的数据集中显示我的每个答案选项的百分比。在某种程度上,我使用下面的代码(我取自代码)得到了期望的结果,但问题是,如果某个特定类别没有值(=0%),那么这将与中心类别的%值冲突 是否有办法修改此代码以防止发生这种情况(例如,不显示等于0的类别百分比,或将它们并排放置) 我的df看起来像这样: Question Entirely Disagree Disagree Neut
- 是否有办法修改此代码以防止发生这种情况(例如,不显示等于0的类别百分比,或将它们并排放置)
Question Entirely Disagree Disagree Neutral Agree Entirely Agree
TQ_3 TQ_3 3 4 4 2 1
TQ_4 TQ_4 1 2 6 5 0
TQ_5 TQ_5 2 3 3 5 1
TQ_6 TQ_6 5 5 0 3 1
TQ_7 TQ_7 0 1 1 6 6
TQ_8 TQ_8 0 2 0 7 5
TQ_9 TQ_9 2 1 4 3 4
TQ_10 TQ_10 2 5 3 2 2
我使用的整个代码如下:
# store the original col names used in custom panel function
origNames = colnames(summd_trDat)
# define a custom panel function
myPanelFunc <- function(...){
panel.likert(...)
vals <- list(...)
DF <- data.frame(x=vals$x, y=vals$y, groups=vals$groups)
### some convoluted calculations here...
grps <- as.character(DF$groups)
for(i in 1:length(origNames)){
grps <- sub(paste0('^',origNames[i]),i,grps)
}
DF <- DF[order(DF$y,grps),]
DF$correctX <- ave(DF$x,DF$y,FUN=function(x){
x[x < 0] <- rev(cumsum(rev(x[x < 0]))) - x[x < 0]/2
x[x > 0] <- cumsum(x[x > 0]) - x[x > 0]/2
return(x)
})
subs <- sub(' Positive$','',DF$groups)
collapse <- subs[-1] == subs[-length(subs)] & DF$y[-1] == DF$y[-length(DF$y)]
DF$abs <- abs(DF$x)
DF$abs[c(collapse,FALSE)] <- DF$abs[c(collapse,FALSE)] + DF$abs[c(FALSE,collapse)]
DF$correctX[c(collapse,FALSE)] <- 0
DF <- DF[c(TRUE,!collapse),]
DF$perc <- round(ave(DF$abs,DF$y,FUN=function(x){x/sum(x) * 100}), 0)
###
panel.text(x=DF$correctX, y=DF$y, label=paste0(DF$perc,'%'), cex=0.7)
}
# plot passing our custom panel function
plot.likert(summd_trDat,
as.percent=TRUE,
main = "Graph title",
xlab = "Percent",
positive.order = F,
ylab = "Question",
key.border.white=F,
panel=myPanelFunc, # ***
rightAxis=F
)
我非常感谢在这方面提供的任何帮助,我在plot.likert()函数中找不到可以这样做的参数,但正如我所提到的,我对这类事情没有太多经验 您应该只替换自定义函数中关于标签的部分
library(HH)
text <- "ID Question Entirely_Disagree Disagree Neutral Agree Entirely_Agree
TQ_3 TQ_3 3 4 4 2 1
TQ_4 TQ_4 1 2 6 5 0
TQ_5 TQ_5 2 3 3 5 1
TQ_6 TQ_6 5 5 0 3 1
TQ_7 TQ_7 0 1 1 6 6
TQ_8 TQ_8 0 2 0 7 5
TQ_9 TQ_9 2 1 4 3 4
TQ_10 TQ_10 2 5 3 2 2"
df <- read.table(text=text, header = TRUE)
origNames = colnames(df)
# define a custom panel function
myPanelFunc <- function(...){
panel.likert(...)
vals <- list(...)
DF <- data.frame(x=vals$x, y=vals$y, groups=vals$groups)
### some convoluted calculations here...
grps <- as.character(DF$groups)
for(i in 1:length(origNames)){
grps <- sub(paste0('^',origNames[i]),i,grps)
}
DF <- DF[order(DF$y,grps),]
DF$correctX <- ave(DF$x,DF$y,FUN=function(x){
x[x < 0] <- rev(cumsum(rev(x[x < 0]))) - x[x < 0]/2
x[x > 0] <- cumsum(x[x > 0]) - x[x > 0]/2
return(x)
})
subs <- sub(' Positive$','',DF$groups)
collapse <- subs[-1] == subs[-length(subs)] & DF$y[-1] == DF$y[-length(DF$y)]
DF$abs <- abs(DF$x)
DF$abs[c(collapse,FALSE)] <- DF$abs[c(collapse,FALSE)] + DF$abs[c(FALSE,collapse)]
DF$correctX[c(collapse,FALSE)] <- 0
DF <- DF[c(TRUE,!collapse),]
DF$perc <- round(ave(DF$abs,DF$y,FUN=function(x){x/sum(x) * 100}), 0)
## Here goes 6 lines that have been changes - AK
# here we modify the column with labels a bit:
DF$perc <- paste0(DF$perc,'%')
# change all "0%" to blanks
DF$perc[DF$perc == "0%"] <- ""
# the argument label is a bit modified too
panel.text(x=DF$correctX, y=DF$y, label=DF$perc, cex=0.7)
}
# plot passing our custom panel function
p <- plot.likert(df,
as.percent=TRUE,
main = "Graph title",
xlab = "Percent",
positive.order = F,
ylab = "Question",
key.border.white=F,
panel=myPanelFunc,
rightAxis=F
)
p
库(HH)
短信嘿,你到底想要什么还不清楚。你能把你的结果的图片(图表)和你想要的结果贴出来吗?你好,非常感谢你的关注。因为我是这个社区的新成员,所以我不能发布图片,但应该有一个链接“我的输出…”如果你看图表,中心的一些百分比无法读取,因为在同一位置显示的百分比不止一个。我想知道是否有办法解决这个问题。(我希望我说得更清楚些。)非常感谢你!这比我想象的要简单得多;-)我真的很感谢你抽出时间来回复我的帖子。希望其他尝试做类似事情的人也能从中受益。
library(HH)
text <- "ID Question Entirely_Disagree Disagree Neutral Agree Entirely_Agree
TQ_3 TQ_3 3 4 4 2 1
TQ_4 TQ_4 1 2 6 5 0
TQ_5 TQ_5 2 3 3 5 1
TQ_6 TQ_6 5 5 0 3 1
TQ_7 TQ_7 0 1 1 6 6
TQ_8 TQ_8 0 2 0 7 5
TQ_9 TQ_9 2 1 4 3 4
TQ_10 TQ_10 2 5 3 2 2"
df <- read.table(text=text, header = TRUE)
origNames = colnames(df)
# define a custom panel function
myPanelFunc <- function(...){
panel.likert(...)
vals <- list(...)
DF <- data.frame(x=vals$x, y=vals$y, groups=vals$groups)
### some convoluted calculations here...
grps <- as.character(DF$groups)
for(i in 1:length(origNames)){
grps <- sub(paste0('^',origNames[i]),i,grps)
}
DF <- DF[order(DF$y,grps),]
DF$correctX <- ave(DF$x,DF$y,FUN=function(x){
x[x < 0] <- rev(cumsum(rev(x[x < 0]))) - x[x < 0]/2
x[x > 0] <- cumsum(x[x > 0]) - x[x > 0]/2
return(x)
})
subs <- sub(' Positive$','',DF$groups)
collapse <- subs[-1] == subs[-length(subs)] & DF$y[-1] == DF$y[-length(DF$y)]
DF$abs <- abs(DF$x)
DF$abs[c(collapse,FALSE)] <- DF$abs[c(collapse,FALSE)] + DF$abs[c(FALSE,collapse)]
DF$correctX[c(collapse,FALSE)] <- 0
DF <- DF[c(TRUE,!collapse),]
DF$perc <- round(ave(DF$abs,DF$y,FUN=function(x){x/sum(x) * 100}), 0)
## Here goes 6 lines that have been changes - AK
# here we modify the column with labels a bit:
DF$perc <- paste0(DF$perc,'%')
# change all "0%" to blanks
DF$perc[DF$perc == "0%"] <- ""
# the argument label is a bit modified too
panel.text(x=DF$correctX, y=DF$y, label=DF$perc, cex=0.7)
}
# plot passing our custom panel function
p <- plot.likert(df,
as.percent=TRUE,
main = "Graph title",
xlab = "Percent",
positive.order = F,
ylab = "Question",
key.border.white=F,
panel=myPanelFunc,
rightAxis=F
)
p