同时使用formattable和plotly

如果同时使用formattable和plotly，则在运行以下代码时会出现错误“最后一个图中的错误（）：最后一个图不存在”，这是Nico Katze在的注释部分中已经提到的问题

库（格式化表）
图书馆（绘本）
DF找到了答案！它实际上是在使用formattable:：但是在style函数上，这似乎是个问题。下面是加载plotly和formattable时正在工作的代码

library(formattable)
library(plotly) 
DF <- data.frame(Ticker=c("", "", "", "IBM", "AAPL", "MSFT"),
                 Name=c("Dow Jones", "S&P 500", "Technology", 
                        "IBM", "Apple", "Microsoft"),
                 Value=accounting(c(15988.08, 1880.33, NA, 
                                    130.00, 97.05, 50.99)),
                 Change=percent(c(-0.0239, -0.0216, 0.021, 
                                  -0.0219, -0.0248, -0.0399)))
DF

formattable(DF, list(
  Name=formatter(
    "span",
    style = x ~ ifelse(x == "Technology", 
                       formattable::style(font.weight = "bold"), NA)),
  Value = color_tile("white", "orange"),
  Change = formatter(
    "span",
    style = x ~ formattable::style(color = ifelse(x < 0 , "red", "green")),
    x ~ icontext(ifelse(x < 0, "arrow-down", "arrow-up"), x)))
)

库（格式化表）
图书馆（绘本）
DF
library(formattable)
library(plotly) 
DF <- data.frame(Ticker=c("", "", "", "IBM", "AAPL", "MSFT"),
                 Name=c("Dow Jones", "S&P 500", "Technology", 
                        "IBM", "Apple", "Microsoft"),
                 Value=accounting(c(15988.08, 1880.33, NA, 
                                    130.00, 97.05, 50.99)),
                 Change=percent(c(-0.0239, -0.0216, 0.021, 
                                  -0.0219, -0.0248, -0.0399)))
DF

formattable(DF, list(
  Name=formatter(
    "span",
    style = x ~ ifelse(x == "Technology", 
                       formattable::style(font.weight = "bold"), NA)),
  Value = color_tile("white", "orange"),
  Change = formatter(
    "span",
    style = x ~ formattable::style(color = ifelse(x < 0 , "red", "green")),
    x ~ icontext(ifelse(x < 0, "arrow-down", "arrow-up"), x)))
)