如何在表中按列设置数字格式(tableGrob)
我一直在尝试学习如何在R中设置输出表格的格式。现在我正在尝试将表格导入并设置列中数字的格式。我希望在某些列中有两个数字,而在某些列(如秩列)中没有。此外,我希望将行名称保留为年-月。如何创建这样的表 注:“萼片带”一栏中的“3”也打印为“3”,而不是“3.0”如何在表中按列设置数字格式(tableGrob),r,R,我一直在尝试学习如何在R中设置输出表格的格式。现在我正在尝试将表格导入并设置列中数字的格式。我希望在某些列中有两个数字,而在某些列(如秩列)中没有。此外,我希望将行名称保留为年-月。如何创建这样的表 注:“萼片带”一栏中的“3”也打印为“3”,而不是“3.0” 库(gtable) 图书馆(网格) 图书馆(gridExtra) 图书馆(动物园) iris像这样的东西可能会帮你找到你想要的格式 library(gtable) library(grid) library(gridExtra) libr
库(gtable)
图书馆(网格)
图书馆(gridExtra)
图书馆(动物园)
iris像这样的东西可能会帮你找到你想要的格式
library(gtable)
library(grid)
library(gridExtra)
library(zoo)
iris <- as.matrix(iris[1:4, 1:3])
rownames(iris)<-as.yearmon(seq(as.Date("2000/1/1"), as.Date("2000/4/1"), by = "month"))
RankColumn<-seq(1, 4, by = 1)
iris<-cbind(iris, RankColumn)
# Create the matrix
iris<- as.matrix(iris)
# a simple function to scale each column to the range [0, 1]
norm <- function(x) {
apply(x, 2, function(y){(y-min(y))/(max(y)-min(y))})
}
# function to format columns
format.column <- function(matrix, colnum, rounding, decimals){
formatted <- format(round(as.numeric(matrix[,colnum]), digits = rounding),nsmall = decimals)
return(formatted)
}
bluecol <- colorRamp(c("#3366EE", "#AABBFF", "#DDDDFF"))(norm(iris))
bluecol <- rgb(bluecol[, 1], bluecol[, 2], bluecol[, 3], max=255)
tt <- ttheme_default(core=list(bg_params=list(fill=bluecol)))
# Set formatting for individual columns
# Adjust these or add additional columns to format as necessary
iris[,1] <- format.column(matrix = iris, colnum = 1, rounding = 2, decimals = 2)
iris[,2] <- format.column(matrix = iris, colnum = 2, rounding = 2, decimals = 1)
g <- tableGrob(iris, theme=tt)
g <- gtable_add_grob(g,
grobs = rectGrob(gp = gpar(fill = NA, lwd = 2)),
t = 2, b = nrow(g), l = 1, r = ncol(g))
g <- gtable_add_grob(g,
grobs = rectGrob(gp = gpar(fill = NA, lwd = 2)),
t = 1, l = 1, r = ncol(g))
grid.draw(g)
库(gtable)
图书馆(网格)
图书馆(gridExtra)
图书馆(动物园)
iris像这样的东西可能会帮你找到你想要的格式
library(gtable)
library(grid)
library(gridExtra)
library(zoo)
iris <- as.matrix(iris[1:4, 1:3])
rownames(iris)<-as.yearmon(seq(as.Date("2000/1/1"), as.Date("2000/4/1"), by = "month"))
RankColumn<-seq(1, 4, by = 1)
iris<-cbind(iris, RankColumn)
# Create the matrix
iris<- as.matrix(iris)
# a simple function to scale each column to the range [0, 1]
norm <- function(x) {
apply(x, 2, function(y){(y-min(y))/(max(y)-min(y))})
}
# function to format columns
format.column <- function(matrix, colnum, rounding, decimals){
formatted <- format(round(as.numeric(matrix[,colnum]), digits = rounding),nsmall = decimals)
return(formatted)
}
bluecol <- colorRamp(c("#3366EE", "#AABBFF", "#DDDDFF"))(norm(iris))
bluecol <- rgb(bluecol[, 1], bluecol[, 2], bluecol[, 3], max=255)
tt <- ttheme_default(core=list(bg_params=list(fill=bluecol)))
# Set formatting for individual columns
# Adjust these or add additional columns to format as necessary
iris[,1] <- format.column(matrix = iris, colnum = 1, rounding = 2, decimals = 2)
iris[,2] <- format.column(matrix = iris, colnum = 2, rounding = 2, decimals = 1)
g <- tableGrob(iris, theme=tt)
g <- gtable_add_grob(g,
grobs = rectGrob(gp = gpar(fill = NA, lwd = 2)),
t = 2, b = nrow(g), l = 1, r = ncol(g))
g <- gtable_add_grob(g,
grobs = rectGrob(gp = gpar(fill = NA, lwd = 2)),
t = 1, l = 1, r = ncol(g))
grid.draw(g)
库(gtable)
图书馆(网格)
图书馆(gridExtra)
图书馆(动物园)
iris虽然功能强大且灵活,但我发现Matt的格式
功能有点过于复杂。一点sprintf
就足够了。此外,将yearmon
对象转换为字符将保留格式
library(gtable)
library(grid)
library(gridExtra)
library(zoo)
data(iris)
iris <- iris[1:4, 1:3]
rownames(iris) <- as.character(as.yearmon(
seq(as.Date("2000/1/1"), as.Date("2000/4/1"), by = "month")))
iris$RankColumn <- 1:nrow(iris)
# a simple function to scale each row or column to the range [0, 1]
# will convert characters to numerics if in a sensible format
norm <- function(x, mar=2) {
rnames <- rownames(x)
x <- apply(x, 2, as.numeric)
x <- apply(x, mar, function(y){(y-min(y))/(max(y)-min(y))})
rownames(x) <- rnames
x
}
# function to pad with zero
# by default does not pad integers
zeropad <- function(x, nz=1, exc.int=TRUE) {
if (is.integer(x) & exc.int) {
x
} else {
sprintf(paste0("%.", nz, "f"), x)
}
}
bluecol <- colorRamp(c("#3366EE", "#AABBFF", "#DDDDFF"))(norm(iris))
bluecol <- rgb(bluecol[, 1], bluecol[, 2], bluecol[, 3], max=255)
tt <- ttheme_default(core=list(bg_params=list(fill=bluecol)))
# convert floats to zero-padded characters
iris[1:ncol(iris)] <- sapply(iris, zeropad, 2)
g <- tableGrob(iris, theme=tt)
g <- gtable_add_grob(g,
grobs = rectGrob(gp = gpar(fill = NA, lwd = 2)),
t = 2, b = nrow(g), l = 1, r = ncol(g))
g <- gtable_add_grob(g,
grobs = rectGrob(gp = gpar(fill = NA, lwd = 2)),
t = 1, l = 1, r = ncol(g))
plot.new()
grid.draw(g)
库(gtable)
图书馆(网格)
图书馆(gridExtra)
图书馆(动物园)
数据(iris)
iris虽然功能强大且灵活,但我发现Matt的格式
功能有点过于复杂。一点sprintf
就足够了。此外,将yearmon
对象转换为字符将保留格式
library(gtable)
library(grid)
library(gridExtra)
library(zoo)
data(iris)
iris <- iris[1:4, 1:3]
rownames(iris) <- as.character(as.yearmon(
seq(as.Date("2000/1/1"), as.Date("2000/4/1"), by = "month")))
iris$RankColumn <- 1:nrow(iris)
# a simple function to scale each row or column to the range [0, 1]
# will convert characters to numerics if in a sensible format
norm <- function(x, mar=2) {
rnames <- rownames(x)
x <- apply(x, 2, as.numeric)
x <- apply(x, mar, function(y){(y-min(y))/(max(y)-min(y))})
rownames(x) <- rnames
x
}
# function to pad with zero
# by default does not pad integers
zeropad <- function(x, nz=1, exc.int=TRUE) {
if (is.integer(x) & exc.int) {
x
} else {
sprintf(paste0("%.", nz, "f"), x)
}
}
bluecol <- colorRamp(c("#3366EE", "#AABBFF", "#DDDDFF"))(norm(iris))
bluecol <- rgb(bluecol[, 1], bluecol[, 2], bluecol[, 3], max=255)
tt <- ttheme_default(core=list(bg_params=list(fill=bluecol)))
# convert floats to zero-padded characters
iris[1:ncol(iris)] <- sapply(iris, zeropad, 2)
g <- tableGrob(iris, theme=tt)
g <- gtable_add_grob(g,
grobs = rectGrob(gp = gpar(fill = NA, lwd = 2)),
t = 2, b = nrow(g), l = 1, r = ncol(g))
g <- gtable_add_grob(g,
grobs = rectGrob(gp = gpar(fill = NA, lwd = 2)),
t = 1, l = 1, r = ncol(g))
plot.new()
grid.draw(g)
库(gtable)
图书馆(网格)
图书馆(gridExtra)
图书馆(动物园)
数据(iris)
iris我相信您必须将“apply(iris[,-4],2,zeropad)”一行更改为mapply(zeropad,iris[,-4],2)@user2946746:两者都可以工作。如果你想用两个零填充,你可以这样做:apply(iris[,-4],2,zeropad,2)
,mapply(zeropad,iris[,-4],2)
或sapply(iris[,-4],zeropad,2)
。它们都会给出相同的结果。我倾向于在数组和矩阵上使用apply
,在类似列表的对象(包括数据帧)上使用*apply
(包括mapply
和sapply
)。谢谢,我尝试以不同的格式设置每一列。iris[,c(1)]如果在应用颜色函数之前对列进行格式化,它将无法正常工作,因为格式化会将数字转换为字符,并且无法对字符进行数学运算(至少不能直接进行)。如果字符的格式可以理解为数字,则可以对其进行转换。试试看:ch我也想出了一个解决办法。iris[]我认为您必须将“apply(iris[,-4],2,zeropad)”一行更改为mapply(zeropad,iris[,-4],2)@user2946746:两者都可以工作。如果你想用两个零填充,你可以这样做:apply(iris[,-4],2,zeropad,2)
,mapply(zeropad,iris[,-4],2)
或sapply(iris[,-4],zeropad,2)
。它们都会给出相同的结果。我倾向于在数组和矩阵上使用apply
,在类似列表的对象(包括数据帧)上使用*apply
(包括mapply
和sapply
)。谢谢,我尝试以不同的格式设置每一列。iris[,c(1)]如果在应用颜色函数之前对列进行格式化,它将无法正常工作,因为格式化会将数字转换为字符,并且无法对字符进行数学运算(至少不能直接进行)。如果字符的格式可以理解为数字,则可以对其进行转换。试试看:ch我也想出了一个解决办法。iris[]我注意到图表丢失了颜色的格式。它们不再是按列而是按列。我注意到图表丢失了颜色的格式。它们不再是按列而是按列。