使用for循环在R中使用manova？ anova_test

首先，您不需要将整个数据传递到

anova_test

函数中，因为您已经在两个块中传递了它

然后在建模行中，您需要提供实际数据，而不仅仅是列名，并且不需要指定数据集，因为您已经提供了数据

例如：

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最后，我不知道你为什么想要这么多这样的成对manova，也许有更好的方法来做你想做的事情（从统计学上讲）

考虑用

expand.grid

捕获两组列名的所有可能组合，然后用

Map

调用一个元素循环（包装到

mappy

）而不是三级嵌套的

for

循环，这些循环不会将结果保存到任何对象

 res <- manova(cbind(get(colnames(dataOne)[i]), get(colnames(dataOne)[k])) ~ get(colnames(dataTwo)[j]), data = dataSet)

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在循环中你有res，然后你调用summary（res.man）。。也许您先尝试修复此问题，看看错误是否仍然存在？

Error in `[[<-.data.frame`(`*tmp*`, i, value = 1:2) : 
  replacement has 2 rows, data has 1
De plus : Warning message:
In storage.mode(v) <- "double" :

 Error in `[[<-.data.frame`(`*tmp*`, i, value = 1:2) : 
  replacement has 2 rows, data has 1

res <- manova(dataOne[,c(i,k)] ~ dataTwo[,j])

 res <- manova(cbind(get(colnames(dataOne)[i]), get(colnames(dataOne)[k])) ~ get(colnames(dataTwo)[j]), data = dataSet)

# BUILD DATA FRAME OF ALL POSSIBLE COMBINATIONS
params_df <- expand.grid(cat1 = c("age", "child", "balance", "previous"),
                         cat2 = c("age", "child", "balance", "previous"),
                         quant = c("job", "marital", "education", "default", 
                                   "housing", "loan", "contact", "month"))

# REMOVE ROWS WHERE CATEGORIES ARE THE SAME
params_df <- subset(params_df, cat1 != cat2)


# USER-DEFINED METHOD TO CALL manova WITH DYNAMIC FORMULA AND RESULTS
anova_test <- function(dataSet, cat1, cat2, quant) {

   frml <- as.formula(paste0("cbind(", cat1, ",", cat2, ") ~ ", quant))
   res.man <- manova(frml, data = dataSet) 

   res.list <- list(estimates = summary(res.man),
                    aov = summary.aov(res.man))

   return(res.list)
}

# RETREIVE DATA
D <- apply_impute(data)

# BUILD LIST OF MANOVA RESULTS
manova_list <- Map(anova_test, 
                   cat1 = params_df$cat1,
                   cat2 = params_df$cat2, 
                   quant = params_df$quant,
                   MoreArgs = list(dataSet = D))

# DISPLAY SELECT RESULTS BY INDEX AND NAMES
manova_list[[1]]$estimates       
manova_list[[1]]$aov

manova_list[[2]]$estimates
manova_list[[2]]$aov
# ...


# DISPLAY ALL RESULTS
lapply(manova_list, `[[`, "estimates")
lapply(manova_list, `[[`, "aov")