knn3中的错误。矩阵（x，y=y，k=k，…）：在R中尝试进行knn分类时，y必须是因子错误

我试图用10倍交叉验证来进行knn。然而，当我尝试将数据拟合到模型时，我遇到了一个错误，上面写着“knn3.matrix（x，y=y，k=k，…）中的错误：y必须是一个因子”。有人能就如何解决此错误向我提供建议吗

class <- c("Not", "Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not","Not", "Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor","Tumor")

class欢迎使用堆栈溢出！这将允许其他人帮助你。我试图复制您的数据，但没有提供对象“cernical”和“logged_-nzv”。
df1<-data.frame(cervical[1:58, 0],class)
df2 <- as.data.frame(logged_standardized_nzv)

merge <- merge(df1, df2, by = "row.names")
rownames(merge)<- merge[,1]
merge <- merge[,-1]

set.seed(100)
intrain <- createDataPartition(y = merge[ ,1], p=0.7)[[1]]

training <- merge[intrain, ]
testing <-  merge[-intrain, ]

knn.fit <-knn3(x = training[,-1],
               y = training[ ,1], k=10)

# Error in knn3.matrix(x, y = y, k = k, ...) : y must be a factor