Reactjs 映射函数中的If/Else作出反应
我有个问题。我必须建立一个应用程序,人们可以从lastFm搜索音乐。到目前为止还不错,我已经做了一些正常工作的事情,但我在地图功能中的if/else有问题,我尝试向用户显示没有找到任何结果(如果有),但没有运气。如果有1+个结果,将显示在屏幕上,但如果有任何结果,则不会发生任何事情。这是我的密码Reactjs 映射函数中的If/Else作出反应,reactjs,Reactjs,我有个问题。我必须建立一个应用程序,人们可以从lastFm搜索音乐。到目前为止还不错,我已经做了一些正常工作的事情,但我在地图功能中的if/else有问题,我尝试向用户显示没有找到任何结果(如果有),但没有运气。如果有1+个结果,将显示在屏幕上,但如果有任何结果,则不会发生任何事情。这是我的密码 import React, { Component } from 'react'; import AppBar from '@material-ui/core/AppBar'; import Toolb
import React, { Component } from 'react';
import AppBar from '@material-ui/core/AppBar';
import Toolbar from '@material-ui/core/Toolbar';
import Typography from '@material-ui/core/Typography';
import {
TextField,
Button,
List,
ListItem,
ListItemAvatar,
ListItemText,
Avatar,
Card,
CardContent
} from '@material-ui/core';
import axios from 'axios';
import './App.css';
const API_URL = 'http://ws.audioscrobbler.com/2.0/?limit=5&format=json&method=artist.search&api_key=' + process.env.REACT_APP_LASTFM_APPKEY;
const isEmpty = (str) => str.length === 0;
class App extends Component {
state = {
searchTerm: '',
savedArtists: []
}
componentDidMount() {
const existing = localStorage.getItem('savedArtists')
if (existing) {
this.setState({ savedArtists: JSON.parse(existing) })
}
}
onTextChange = (event) => {
const value = event.target.value;
this.setState({ searchTerm: value });
}
search = (terms) => {
const request = API_URL + '&artist=' + terms;
axios.get(request).then((response) => {
const results = response.data.results;
const artists = results.artistmatches.artist.map((artist) => {
const avatarImage = artist.image.find(image => image.size === 'medium');
const imageUrl = avatarImage['#text'];
return { ...artist, avatar: imageUrl }
});
this.setState({ artists });
})
}
onSearchClick = () => {
this.search(this.state.searchTerm);
}
clearSearch = () => {
this.setState({
searchTerm: '',
artists: []
})
}
onResultClick = (artist) => {
this.clearSearch();
const savedArtists = this.state.savedArtists;
savedArtists.push(artist)
this.setState({ savedArtists: savedArtists })
localStorage.setItem('savedArtists', JSON.stringify(savedArtists));
}
render() {
const results = this.state.artists || [];
return (
<div className="App">
<header className="App-header">
<AppBar position="static" color="primary">
<Toolbar className="search-bar">
<Typography variant="h6" color="inherit">
Photos
</Typography>
<TextField
placeholder="Search on Last.fm"
className="search-input"
onChange={this.onTextChange}
value={this.state.searchTerm}
/>
<Button
onClick={this.onSearchClick}
variant="contained"
color="secondary"
disabled={isEmpty(this.state.searchTerm)}
>
Search
</Button>
{!isEmpty(this.state.searchTerm) && (
<Button
onClick={this.clearSearch}
variant="contained"
>
Clear
</Button>)
}
</Toolbar>
</AppBar>
</header>
//****Here is where i've try to use if/else
<List className="search-results">
{
results.map((artist ,results) => {
if(results.length === 0)
return (<ListItem> Not Found</ListItem>
); else {
return ( <ListItem
button
key={artist.name}
className="result"
onClick={() => this.onResultClick(artist)}
>
<ListItemAvatar>
<Avatar src={artist.avatar} alt={artist.name} />
</ListItemAvatar>
<ListItemText primary={artist.name} />
<Button
variant="outlined"
color="secondary"
size="small"
className="add-button"
>
Add to favorites
</Button>
</ListItem>);
}
})
}
</List>
<div className="artist-container">
{
this.state.savedArtists.map((artist, i) => {
return (
<Card className="artist-card"
key={i}
>
<CardContent>
{artist.name}
</CardContent>
</Card>
)
})
}
</div>
</div>
);
}
}
export default App;
你犯了一个错误。它是.mapresult:any,index:number,original:[],所以您引用的是带有参数结果的索引号:
因此,只需通过不将结果引用为.map的参数来解决此问题。问题在于,您试图在数组的映射中执行if/else。但是如果数组中没有项目,那么就没有要映射的内容 要做的是使用三元数组检查数组是否有任何结果:
{ results && result.length ?
<List className="search-results">
{
results.map((artist) => {
return (
<ListItem button key={artist.name} className="result" onClick={() => this.onResultClick(artist)} >
<ListItemAvatar>
<Avatar src={artist.avatar} alt={artist.name} />
</ListItemAvatar>
<ListItemText primary={artist.name} />
<Button
variant="outlined"
color="secondary"
size="small"
className="add-button"
>
Add to favorites
</Button>
</ListItem>
);
})
}
</List>
: <div>No Results</div>
}
在这里,我们正在检查results.length是否被认为是真实的,如果它是1或更高,那么它将呈现您的列表,否则它将呈现我们的div,通知用户没有结果,您可以将其更改为您想要的任何结果。是的,它有效,但是我只想在用户单击Search时显示“no results”(无结果)。一个快速而肮脏的解决方案是在状态中添加一些东西,如searched(已搜索),这是一个布尔值,在用户搜索后设置为true,然后通过将其设为results&&result.length | |来检查三元值!这个州被搜查了。不过,可能还有更好的方法。我会试试这个。泰
{ results && result.length ?
<List className="search-results">
{
results.map((artist) => {
return (
<ListItem button key={artist.name} className="result" onClick={() => this.onResultClick(artist)} >
<ListItemAvatar>
<Avatar src={artist.avatar} alt={artist.name} />
</ListItemAvatar>
<ListItemText primary={artist.name} />
<Button
variant="outlined"
color="secondary"
size="small"
className="add-button"
>
Add to favorites
</Button>
</ListItem>
);
})
}
</List>
: <div>No Results</div>
}