Regex 用于提取括号之间单词的Swift正则表达式

你好，我想提取（）之间的文本

例如：

(some text) some other text -> some text
(some) some other text      -> some
(12345)  some other text    -> 12345

括号之间字符串的最大长度应为10个字符

(TooLongStri) -> nothing matched because 11 characters

我目前拥有的是：

let regex   = try! NSRegularExpression(pattern: "\\(\\w+\\)", options: [])

regex.enumerateMatchesInString(text, options: [], range: NSMakeRange(0, (text as NSString).length))
{
    (result, _, _) in
        let match = (text as NSString).substringWithRange(result!.range)

        if (match.characters.count <= 10)
        {
            print(match)
        }
}

与不匹配这将起作用

\((?=.{0,10}\)).+?\)

这也会起作用

\((?=.{0,10}\))([^)]+)\)

正则表达式分解

你可以用

"(?<=\\()[^()]{1,10}(?=\\))"

看。您需要的值位于捕获组1内

\( #Match the bracket literally
(?=.{0,10}\)) #Lookahead to check there are between 0 to 10 characters till we encounter another )
([^)]+) #Match anything except )
\) #Match ) literally

"(?<=\\()[^()]{1,10}(?=\\))"

"\\(([^()]{1,10})\\)"