Regex 使用正则表达式忽略新行字符

我有以下模板1000次，需要提取库与\n\n\n\n之间的值：

如何使用正则表达式和perl实现这一点

if ( $str =~ (?:library\s?)(.*?)(?:\\n|$) ) {
    $field = $1;
}

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应该捕获x.y.z值，只要字符串前面始终有单词库。只有在找到匹配项时，才会填充regex$1值。

能否正确设置格式？我真的没有得到你想要的。。。

my $template = "this identifier L99203 which is blah\n\nto the idnetifier of the library x.y.z\n\n\n\nYou should use this number for your solution to be right\n\n\n\no yes\n\n\n\nconnect ot db " x 1000;
my @values = $template =~ /of the library (.*)\n\n\n\n/g;

my $template = "this identifier L99203 which is blah\n\nto the idnetifier of the library x.y.z\n\n\n\nYou should use this number for your solution to be right\n\n\n\no yes\n\n\n\nconnect ot db " x 1000;
my @values = $template =~ /of the library (.*)\n\n\n\n/g;