Regex Perl：用除空格以外的所有字符分割字符串
我想用除空格以外的所有字符分割字符串 示例： 假设我有一个字符串：Regex Perl：用除空格以外的所有字符分割字符串,regex,perl,split,whitespace,inverse,Regex,Perl,Split,Whitespace,Inverse,我想用除空格以外的所有字符分割字符串 示例： 假设我有一个字符串： "The quick brown fox jumps over the lazy dog" 我想拆分它并获得以下空间字符串列表： [" ", " ", " ", " ", " ", " ", " ", " "] 你能告诉我怎么做吗 谢谢 您可以使用\S按此处分割，这意味着匹配任何非空白字符 my @list = split /\S+/, $string; 或者更好的是，只需匹配您的空格，
"The quick brown fox jumps over the lazy dog"
[" ", " ", " ", " ", " ", " ", " ", " "]
谢谢 您可以使用
\Smy @list = split /\S+/, $string;
my @list = $string =~ /\s+/g;
您可以使用
\Smy @list = split /\S+/, $string;
my @list = $string =~ /\s+/g;
您可以使用
\Smy @list = split /\S+/, $string;
my @list = $string =~ /\s+/g;
您可以使用
\Smy @list = split /\S+/, $string;
my @list = $string =~ /\s+/g;
\S\Smy $string = q{The quick brown fox jumps over the lazy dog};
my @values = split /[^ ]+/, $string;
\S\Smy $string = q{The quick brown fox jumps over the lazy dog};
my @values = split /[^ ]+/, $string;
\S\Smy $string = q{The quick brown fox jumps over the lazy dog};
my @values = split /[^ ]+/, $string;
\S\Smy $string = q{The quick brown fox jumps over the lazy dog};
my @values = split /[^ ]+/, $string;
为什么不直接查找空格而不是按非空格字符分割？
pattern=
（\s+）pattern=
（\s+）pattern=
（\s+）pattern=
（\s+++++