Regex Powershell解析

我从GIT日志中获得以下输入：

Merge: d9335ae 7d12d50
Author: name\name <mail@mail.com>
Date:   Wed Oct 31 12:55:00 2018 -0500

id:202847 Merge branch 'release/2.6.0' into release/3.0.0

# Conflicts:
#   configuration/path/path

---

PowerShell具有非常强大的本机Regex支持，您可以非常轻松地从git命令中检索ID值，如下所示。我们首先捕获git命令的输出在我的例子中，我将它粘贴到一个var中，但您也可以运行$commitsg=git commit 202847以另一种方式将输出捕获到一个var中：

$r="Merge: d9335ae 7d12d50
Author: name\name <mail@mail.com>
Date:   Wed Oct 31 12:55:00 2018 -0500

id:202847 Merge branch 'release/2.6.0' into release/3.0.0

# Conflicts:
#   configuration/path/path"

您可以将该输出存储在变量中，如下所示：

$CommitID = [regex]::Match($r, "id:(.....)\w+").Value

然后使用字符串扩展将其嵌入到其他命令中，如下所示：

"TP $CommitID Professional Lines: 2,800,000 Policy Aggregate Limit update"
>TP Id:202847 Professional Lines: 2,800,000 Policy Aggregate Limit update

---

要提供更具PowerShell风格的替代方案，请执行以下操作：

# Sample log text (multi-line string in the form of a here-string).
$logText = @'
Merge: d9335ae 7d12d50
Author: name\name <mail@mail.com>
Date:   Wed Oct 31 12:55:00 2018 -0500

id:202847 Merge branch 'release/2.6.0' into release/3.0.0

# Conflicts:
#   configuration/path/path
'@

# Extract the ID number alone, via a capture group `(...)`, using the
# -match regex operator and the automatic $Matches variable that reflects the 
# results.
# Entry 1 of $Matches contains the 1st (and here only) capture-group value.
# \b is used to make the regex more robust, by only matching at word boundaries.
# With the sample input, $id receives value '202847'
$id = if ($logText -match '\bid:(\d+)\b') { $Matches[1] }

# Note: If your input comes directly from a *file*, say 'commit.log', 
#       use the following command instead:
#
#  $id = (Select-String -list '\bid:(\d+)\b' commit.log).Matches.Groups[1].Value
#
# Alternatively, if reading the whole file into memory at once is acceptable,
# pass (Get-Content -Raw commit.log) instead of $logText to -match.

# Build the desired output string from the ID obtained and the API return value.
"TP Id:$id " + $returnValFromApi

---

太好了——这正是我需要的——但有一个问题。当API只接受诸如202847之类的编号时，它将id:xxxxx传递到我的目标进程API中。我如何让正则表达式只修补以下6位数字：？抱歉-我对regex还不熟悉，并且边走边学习：我想你指的是git show，而不是git commit。正则表达式id:……\w+与其描述不匹配：您正在捕获id:，后跟5个字符，后跟一个或多个单词字符；你的意思是像id:.{6}\b这样的东西吗？另外，我不认为这里讨论的ID是Git提交ID；它们似乎是提交消息的一部分，因此OP自己的正则表达式在本质上可能就足够了：id:\d+奇怪的巧合是，您在我自己的答案之后提供了另一个答案，然后我的答案现在被否决了。“非常奇怪。这不是巧合，@FoxDeploy；事实上，这是我的标准MO：a如果我没有看到满意的答案，我会发布我自己的。b独立地说，如果我发现别人的答案有问题，我会留下一条评论，努力参与对话，希望得到正确的答案。一般来说，可能没有什么需要纠正的，但这只会在关于评论的对话过程中出现。如果在一段合理的时间后，我没有得到任何回应，我就投反对票。这就是这里发生的事情。有什么奇怪的吗？@FoxDeploy:如果达成共识并相应更新答案，我总是很乐意撤销否决票，甚至将其转换为赞成票。嗨，事后看来，我认为你对这个问题给出了一个非常好的答案，没有什么不快的感觉：。我想知道您是否知道哪个git命令实际生成了他给我们的输出？我一直在git show和其他命令中搜寻，找不到一个提供id:message here格式的命令。我感谢您的安抚性反馈，@FoxDeploy。我认为所讨论的ID与Git无关，只是碰巧是用户选择的提交消息的一部分，可能它链接到Git之外的系统。

"TP $CommitID Professional Lines: 2,800,000 Policy Aggregate Limit update"
>TP Id:202847 Professional Lines: 2,800,000 Policy Aggregate Limit update

# Sample log text (multi-line string in the form of a here-string).
$logText = @'
Merge: d9335ae 7d12d50
Author: name\name <mail@mail.com>
Date:   Wed Oct 31 12:55:00 2018 -0500

id:202847 Merge branch 'release/2.6.0' into release/3.0.0

# Conflicts:
#   configuration/path/path
'@

# Extract the ID number alone, via a capture group `(...)`, using the
# -match regex operator and the automatic $Matches variable that reflects the 
# results.
# Entry 1 of $Matches contains the 1st (and here only) capture-group value.
# \b is used to make the regex more robust, by only matching at word boundaries.
# With the sample input, $id receives value '202847'
$id = if ($logText -match '\bid:(\d+)\b') { $Matches[1] }

# Note: If your input comes directly from a *file*, say 'commit.log', 
#       use the following command instead:
#
#  $id = (Select-String -list '\bid:(\d+)\b' commit.log).Matches.Groups[1].Value
#
# Alternatively, if reading the whole file into memory at once is acceptable,
# pass (Get-Content -Raw commit.log) instead of $logText to -match.

# Build the desired output string from the ID obtained and the API return value.
"TP Id:$id " + $returnValFromApi