Reporting services 将单个参数的多个值从SSRS传递到配置单元

对上述问题有什么答案吗？。我也遇到了同样的问题：

SSRS端的查询是：

select *
from xyz.test_table1
where f1 in (?)

在本例中，我的数据源是一个配置单元表。用户对参数的选择是一个多值参数，我希望将其替换为：

where in ('value1','value2')

当执行查询时。但是，当查看配置单元端的查询执行时，会发现：

where in ('value1,value2')

我怎样才能解决这个问题

从文档中可以看出，配置单元查询语言似乎支持公共表表达式

因此，类似于以下内容的工作应该是可行的：

---

如果您不想在所有数据集中都使用这种僵化的方式，那么您需要将这种逻辑封装到SQL Server表值参数的配置单元等价物中，可能是

在SQL Server中，函数的定义如下：

create function [dbo].[fn_StringSplit4k]
(
  @str nvarchar(4000) = ' '        -- String to split.
 ,@delimiter as nvarchar(1) = ','  -- Delimiting value to split on.
 ,@num as int = null               -- Which value to return.
)
returns table
as
return
     -- Start tally table with 10 rows.
 with n(n)   as (select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1)

     -- Select the same number of rows as characters in @str as incremental row numbers.
     -- Cross joins increase exponentially to a max possible 10,000 rows to cover largest @str length.
  ,t(t)   as (select top (select len(isnull(@str,'')) a) row_number() over (order by (select null)) from n n1,n n2,n n3,n n4)

     -- Return the position of every value that follows the specified delimiter.
  ,s(s)   as (select 1 union all select t+1 from t where substring(isnull(@str,''),t,1) = @delimiter)

     -- Return the start and length of every value, to use in the SUBSTRING function.
     -- ISNULL/NULLIF combo handles the last value where there is no delimiter at the end of the string.
  ,l(s,l) as (select s,isnull(nullif(charindex(@delimiter,isnull(@str,''),s),0)-s,4000) from s)

 select rn
          ,item
 from(select row_number() over(order by s) as rn
    ,substring(@str,s,l) as item
  from l
  ) a
 where rn = @num
  or @num is null;

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明白了！为其他用户发布答案

以如下表达式提供查询（在SSRS中的查询下）：

=“从xyz.test_表1中选择*，其中f1位于（'”&Join（参数！参数值，'，'）&'）

上述字符串操作转换为：

从xyz.test_表1中选择*，其中f1位于（'value1'，'value2'）中

---

注意：值1、值2这是用户选择的多值参数的值

您的确切问题是什么？您到底想用什么格式传递值，传递的原因是什么？SSRS端查询的可能重复项类似于xyz.test_table1中的select*，其中f1在（？）。在本例中，我的数据源是一个配置单元表。用户对参数的选择是一个多值参数，我希望在执行查询时将其替换为where in（'value1'，'value2'）。但是当查看配置单元端的查询执行时，它是where in（'value1，value2）。我该如何解决这个问题？*但当我在配置单元端查看查询执行时，我个人对配置单元（value1，value2）不太熟悉，尤其是从SSR查询时。您的数据集脚本是否需要用配置单元查询语言编写？

create function [dbo].[fn_StringSplit4k]
(
  @str nvarchar(4000) = ' '        -- String to split.
 ,@delimiter as nvarchar(1) = ','  -- Delimiting value to split on.
 ,@num as int = null               -- Which value to return.
)
returns table
as
return
     -- Start tally table with 10 rows.
 with n(n)   as (select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1)

     -- Select the same number of rows as characters in @str as incremental row numbers.
     -- Cross joins increase exponentially to a max possible 10,000 rows to cover largest @str length.
  ,t(t)   as (select top (select len(isnull(@str,'')) a) row_number() over (order by (select null)) from n n1,n n2,n n3,n n4)

     -- Return the position of every value that follows the specified delimiter.
  ,s(s)   as (select 1 union all select t+1 from t where substring(isnull(@str,''),t,1) = @delimiter)

     -- Return the start and length of every value, to use in the SUBSTRING function.
     -- ISNULL/NULLIF combo handles the last value where there is no delimiter at the end of the string.
  ,l(s,l) as (select s,isnull(nullif(charindex(@delimiter,isnull(@str,''),s),0)-s,4000) from s)

 select rn
          ,item
 from(select row_number() over(order by s) as rn
    ,substring(@str,s,l) as item
  from l
  ) a
 where rn = @num
  or @num is null;