Neo4j Rest Cypher Qyery匹配节点：错误_Rest_Cypher

Neo4j Rest Cypher Qyery匹配节点：错误

rest

Neo4j Rest Cypher Qyery匹配节点：错误,rest,cypher,Rest,Cypher,我正在使用REST API发送cypher查询，如下所示： MATCH (user:Profile)-[:HAS_SEARCHED]-(term{name:"TV"}) WITH [x in collect(user)| id(x) ] AS userIDs MATCH(user:Profile) where id(user) in userIDs MATCH (user)-[r:HAS_SEARCHED]->(term:SearchTerm) return term.name

我正在使用REST API发送cypher查询，如下所示：

MATCH (user:Profile)-[:HAS_SEARCHED]-(term{name:"TV"}) 
WITH [x in collect(user)| id(x) ] AS userIDs 
MATCH(user:Profile) where id(user) in userIDs 
MATCH (user)-[r:HAS_SEARCHED]->(term:SearchTerm) 
return term.name

尽管直接在服务器上运行时查询执行良好，但在eclipse中出现以下错误：

{"results":[],"errors":[{"code":"Neo.ClientError.Request.InvalidFormat",
"message":"Unable to deserialize request: 
Unexpected character ('T' (code 84)): was expecting comma to separate OBJECT entries\n at 
[Source: HttpInputOverHTTP@2543f0f2; line: 1, column: 85]"}]}

请帮忙！！感谢您的查询，您无需两次匹配用户：

MATCH (user:Profile)-[:HAS_SEARCHED]-(term:SearchTerm {name:"TV"}) 
WITH distinct user
MATCH (user)-[r:HAS_SEARCHED]->(term:SearchTerm) 
RETURN term.name, count(*) as freq

甚至：

MATCH (term:SearchTerm {name:"TV"})<-[:HAS_SEARCHED]-(:Profile)-[:HAS_SEARCHED]->(term:SearchTerm) 
RETURN term.name, count(*) as freq

MATCH（术语：SearchTerm{name:“TV”}）（术语：SearchTerm）
返回term.name，计数（*）为频率

如何使用Using Cypher REST API？听起来好像您发送到服务器的JSON不正确，您能用JSON验证器验证它吗？很抱歉，查询格式不正确。编辑了上面的问题语言。谢谢，我不应该像上面那样传递参数。下面的json工作得很好。POST[{“语句”：[{“语句”：“匹配（用户：配置文件）-[：HAS_SEARCHED]-（term{name:{name}}）与不同的用户匹配（user）-[r:HAS_SEARCHED]->（term:SearchTerm）返回term.name”，“参数”：{“name”：“TV”}]