Ruby on rails Rails4:链接到控制器
我有一个用户的显示页面,其中 1.)路线 2.)用户_controller.rbRuby on rails Rails4:链接到控制器,ruby-on-rails,undefined,ruby-on-rails-4,rails-routing,Ruby On Rails,Undefined,Ruby On Rails 4,Rails Routing,我有一个用户的显示页面,其中 1.)路线 2.)用户_controller.rb class UserController < ApplicationController before_filter :authenticate_user!, only: :show def show @user = User.find_by_name(params[:id]) # for name instead of id @listings = @user.listings end end
class UserController < ApplicationController
before_filter :authenticate_user!, only: :show
def show
@user = User.find_by_name(params[:id]) # for name instead of id
@listings = @user.listings
end
end
2.)车间控制器.rb
class ShopController < ApplicationController
before_filter :authenticate_user!, only: :show
def show
@user = User.find_by_name(params[:id]) # for name instead of id
@listings = @user.listings
end
end
class ShopController
仅当im在用户页面(localhost:3000/users/test)上单击指向控制器的链接时,此操作才有效。然后切换到(localhost:3000/shop/test)
如果我试着点击我得到的任何其他地方的链接
链接是->
<li><%= link_to "My Shop", :controller => "shop", :action => "show" %></li>
“店铺”,:操作=>“展示”%>
我是Rails的新手,如果有人能告诉我这将是非常好的:)首先,按照Rails惯例更正控制器的名称。名称应如下所示 控制器/用户_controller.rb
class UsersController < ApplicationController
before_filter :authenticate_user!, only: :show
def show
@user = User.find(params[:id]) # Because Id can't be same for two users but name can be.
@listings = @user.listings
end
end
class ShopController < ApplicationController
before_filter :authenticate_user!, only: :show
def show
@user = User.find(params[:id]) # Id can't be same for two users but name can be.
@listings = @user.listings
end
end
还是会犯那个错误。我认为这与rails如何获取shop:id或知道链接到哪里有关。由于您使用了
as::shop
,因此应该能够使用
创建链接。您好。是否确实要按名称查找用户?我认为使用id是一种更好的方式。它严格来说是可视化和功能化的。但我不认为这是问题所在:(我认为我的链接是错误的。但我仍然不清楚。你能把你的商店和列出的类放在这里吗。这是一个很小的问题,我正在写答案。你说的类是什么意思?:/我对Rails还是很陌生:)Sry
class UsersController < ApplicationController
before_filter :authenticate_user!, only: :show
def show
@user = User.find(params[:id]) # Because Id can't be same for two users but name can be.
@listings = @user.listings
end
end
class ShopController < ApplicationController
before_filter :authenticate_user!, only: :show
def show
@user = User.find(params[:id]) # Id can't be same for two users but name can be.
@listings = @user.listings
end
end
<%= link_to "My Wonderful Shop", {:controller => "shop", :action => "show", :id => @user.id} %>
get 'shop/:id' => 'shop#show'