Ruby on rails 如何将字符串2012年12月15日转换为Datatime对象

第一次我会得到字符串“2012”，然后是“12月”

在下面的示例中，获取字符串

1,15,30

我应该将它们转换为

Datetime

对象

2012-12-01

2012-12-15

2012-12-30

如何操作？

您有以下字符串：

Date.strptime('2012 December', '%Y %B')
#=> Sat, 01 Dec 2012

date = Date.strptime('2012 December 10', '%Y %B %d')
#=> Mon, 10 Dec 2012

date.strftime("%Y-%m-%d")
#=> "2012-12-10"

[1] pry(main)> str = "2012 December 1,15, 30"
=> "2012 December 1,15, 30"

[2] pry(main)> m = /(?'year'\d*)\s(?'month'[a-zA-Z]*)(?'days'[\d, ]*)/.match str
=> #<MatchData
 "2012 December 1,15, 30"
 year:"2012"
 month:"December"
 days:" 1,15, 30">

您需要从中获取三个日期（12月1日、15日和30日）。首先，从该字符串中获取年、月和日：

[1] pry(main)> str = "2012 December 1,15, 30"
=> "2012 December 1,15, 30"

[2] pry(main)> m = /(?'year'\d*)\s(?'month'[a-zA-Z]*)(?'days'[\d, ]*)/.match str
=> #<MatchData
 "2012 December 1,15, 30"
 year:"2012"
 month:"December"
 days:" 1,15, 30">

您有以下字符串：

[1] pry(main)> str = "2012 December 1,15, 30"
=> "2012 December 1,15, 30"

[2] pry(main)> m = /(?'year'\d*)\s(?'month'[a-zA-Z]*)(?'days'[\d, ]*)/.match str
=> #<MatchData
 "2012 December 1,15, 30"
 year:"2012"
 month:"December"
 days:" 1,15, 30">

您需要从中获取三个日期（12月1日、15日和30日）。首先，从该字符串中获取年、月和日：

[1] pry(main)> str = "2012 December 1,15, 30"
=> "2012 December 1,15, 30"

[2] pry(main)> m = /(?'year'\d*)\s(?'month'[a-zA-Z]*)(?'days'[\d, ]*)/.match str
=> #<MatchData
 "2012 December 1,15, 30"
 year:"2012"
 month:"December"
 days:" 1,15, 30">

您有以下字符串：

[1] pry(main)> str = "2012 December 1,15, 30"
=> "2012 December 1,15, 30"

[2] pry(main)> m = /(?'year'\d*)\s(?'month'[a-zA-Z]*)(?'days'[\d, ]*)/.match str
=> #<MatchData
 "2012 December 1,15, 30"
 year:"2012"
 month:"December"
 days:" 1,15, 30">

您需要从中获取三个日期（12月1日、15日和30日）。首先，从该字符串中获取年、月和日：

[1] pry(main)> str = "2012 December 1,15, 30"
=> "2012 December 1,15, 30"

[2] pry(main)> m = /(?'year'\d*)\s(?'month'[a-zA-Z]*)(?'days'[\d, ]*)/.match str
=> #<MatchData
 "2012 December 1,15, 30"
 year:"2012"
 month:"December"
 days:" 1,15, 30">

您有以下字符串：

[1] pry(main)> str = "2012 December 1,15, 30"
=> "2012 December 1,15, 30"

[2] pry(main)> m = /(?'year'\d*)\s(?'month'[a-zA-Z]*)(?'days'[\d, ]*)/.match str
=> #<MatchData
 "2012 December 1,15, 30"
 year:"2012"
 month:"December"
 days:" 1,15, 30">

您需要从中获取三个日期（12月1日、15日和30日）。首先，从该字符串中获取年、月和日：

[1] pry(main)> str = "2012 December 1,15, 30"
=> "2012 December 1,15, 30"

[2] pry(main)> m = /(?'year'\d*)\s(?'month'[a-zA-Z]*)(?'days'[\d, ]*)/.match str
=> #<MatchData
 "2012 December 1,15, 30"
 year:"2012"
 month:"December"
 days:" 1,15, 30">

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