Ruby on rails 工厂女工倍数通过'；s

我需要创建一些工厂，这些工厂是由多个具有多个直通的组件组成的

这是我的模型

Topic
  has_many :plan_topics
  has_many :plans, :through => :plan_topics

PlanTopic
  belongs_to :plan
  belongs_to :topic

Plan
  has_many :subscriptions
  has_many :members, :through => :subscriptions
  has_many :plan_topics
  has_many :topics, :through => :plan_topics

Subscription
  belongs_to :member
  belongs_to :plan

Member
  has_many :subscriptions
  has_many :plans, :through => :subscriptions

这是我的

Factory.define :topic do |topic|
  topic.name "Operations"
end

Factory.define :plan do |plan|
  plan.title "A test Finance plan"
  plan.price "200"
end

Factory.define :plan_topic do |plan_topic|
  plan_topic.topic {|topic| topic.association(:topic)}
  plan_topic.plan {|plan| plan.association(:plan)}
end

我想做的是这个-工厂（：会员订阅）

---

有什么方法可以做到这一点吗？

考虑在构建后使用

回调来设置所有必需的依赖项。例如：

Factory.define :member_with_subscription, :class => 'Member' do |m|
  m.after_build do |member|
    member.subscriptions << Factory.build(:subscription)
  end
end

Factory.define:member_与_订阅，：class=>'member'do|m|
m、 建造完成后|成员|
member.subscriptions我的做法略有不同，这种方式可能更容易理解：

FactoryGirl.define do
  factory :member_with_description do
    after(:build) do |member|
      member.subscriptions << FactoryGirl.build(:subscription)
    end
  end 
end

FactoryGirl.define do
工厂：带有描述的成员
后（：build）do |成员|
会员订阅
FactoryGirl.define do
  factory :member_with_description do
    after(:build) do |member|
      member.subscriptions << FactoryGirl.build(:subscription)
    end
  end 
end