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Ruby &引用;“中断”;是否删除指定的变量?_Ruby_Rspec_Break - Fatal编程技术网

Ruby &引用;“中断”;是否删除指定的变量?

Ruby &引用;“中断”;是否删除指定的变量?,ruby,rspec,break,Ruby,Rspec,Break,我不明白为什么冠军一开始是赫敏,休息后冠军变成了零。。。 使用break有问题吗 这是我的密码: def pair(users_with_meeting, paired_users, ordered_keys,week) ordered_keys.each do |key| candidates = users_with_meeting[key] - paired_users unless candidates.empty? champi

我不明白为什么冠军一开始是赫敏,休息后冠军变成了零。。。 使用break有问题吗

这是我的密码:

def pair(users_with_meeting, paired_users, ordered_keys,week)    

  ordered_keys.each do |key|    
    candidates = users_with_meeting[key] - paired_users  
    unless candidates.empty?  
      champion = candidates.first 
      puts "ok"
      puts champion.inspect.to_s   
      break    
    end     
  end   

  puts champion.inspect.to_s   

  if champion
    meetings.create! week: week, paired_user: champion
    champion.meetings.create! week: week, paired_user: self
  else
    []
  end

end
以下是我的终端中显示的内容:

Run options: include {:locations=>{"./spec/models/user_spec.rb"=>[117]}}
ok    
#<User id: 1265, email: "Hermione.Granger@example.com", first_name: "Hermione", last_name: "Granger", uid: "Hermione.Granger@example.com", active: true, admin: false, created_at: "2013-09-15 18:09:16", updated_at: "2013-09-15 18:09:16", reset_date: "2013-04-22">
F

Failures:

  1) test
     Failure/Error: ginny.pair(User.with_meeting_for(week[1]), [], User.with_meeting_for(week[1]).keys.sort.reverse, week[2])
     NameError:
       undefined local variable or method `champion' for #<User:0x007f85189179f0>
     # ./app/models/user.rb:64:in `pair'
     # ./spec/models/user_spec.rb:133:in `block (2 levels) in <top (required)>'
运行选项:包括{:位置=>{./spec/models/user_spec.rb=>[117]}
好啊
#
F
失败:
1) 试验
失败/错误:ginny.pair(第[1]周有会议的用户,[],第[1]周有会议的用户。keys.sort.reverse,第[2]周)
名称错误:
未定义的局部变量或方法“champion”#
#./app/models/user.rb:64:in'pair'
#./spec/models/user_spec.rb:133:in'block(2层)in'

出现此错误是因为您在与传递到
每个方法的块绑定的范围内定义了
champion
局部变量。在此块之外,变量值变为
nil
。为了避免这种情况,您可以在调用
每个方法之前预定义变量,如下所示:

def pair(users_with_meeting, paired_users, ordered_keys,week)
  champion = ''
  ordered_keys.each do |key|    
    candidates = users_with_meeting[key] - paired_users  
    unless candidates.empty?  
      champion = candidates.first 
      puts "ok"
      puts champion.inspect.to_s   
      break    
    end     
  end   
  puts champion.inspect.to_s   
  if champion
    meetings.create! week: week, paired_user: champion
    champion.meetings.create! week: week, paired_user: self
  else
    []
  end
end

问问自己:我的
pair
函数在哪里结束?请粘贴
pair
方法的整个代码。最好是正确缩进。
放入champion.inspect.to_s
是不必要的尴尬,因为
inspect
返回一个不需要转换的字符串,
放入champion.inspect
p champion
相同。