Ruby 使用数组将给定数字转换为单词

我正在尝试创建一种方法，用于经典瓶装啤酒的输出

给定一个数字，

@beers

，我想将其转换为该数字的word版本。我想将数字拆分为一个数组，然后与一个数字列表进行比较：

class BeerSong

  attr_accessor :beers

  def initialize(beers)

    if beers > 99
      beers = 99
    elsif beers < 1
      beers = "Zero"
    end
    @beers = beers
  end


  def worded
    num_name = {      
      90 => "Ninety", 80 => "Eighty", 70 => "Seventy",60 => "Sixty",
      50 => "Fifty",40 => "Forty",30 => "Thirty",20 => "Twenty",
      19 => "Nineteen", 18 => "Eighteen",  17 => "Seventeen", 16 => "Sixteen",
      15 => "Fifteen",14 => "Fourteen", 13 =>"Thirteen",  12 => "Twelve",
      11 => "Eleven", 10 => "Ten",  9 => "Nine",8 => "Eight", 7 => "Seven",
      6 => "Six",5 => "Five",4 => "Four",3 => "Three",2 => "Two",1 => "One"
    }


    worded = ""

    beers = @beers

    split_beers = beers.to_s.split

    num_name.each do |number, name|
      split_number = number.to_s.split
      if beers == number
        worded << name
      else
        number > 19 && split_number[0].to_i == split_beers[0].to_i
        worded << name
        worded << "-"
      end
    end

    num_name.each do |number, name|
      if number < 10 && split_beers[1].to_i == number
        worded << name
      end
    end

    worded

  end

  def print_song

    while @beers.to_i > 2

      puts "#{worded} bottles of beer on the wall,"
      puts "#{worded} bottles of beer,"
      puts "Take one down, pass it around,"
      @beers -= 1
      puts "#{worded} bottles of beer on the wall.\n\n"
    end

    if @beers.to_i == 2
      puts "#{worded} bottles of beer on the wall,"
      puts "#{worded} bottles of beer,"
      puts "Take one down, pass it around,"
      @beers -= 1
      puts "#{worded} bottle of beer on the wall.\n\n"
    end

    if @beers.to_i == 1
      puts "#{worded} bottle of beer on the wall,"
      puts "#{worded} bottle of beer,"
      puts "Take one down, pass it around,"
      puts "Zero bottles of beer on the wall.\n\n"
    end

    if @beers.to_i == 0
      print ""
    end

  end

end

classbeersong
属性存取器：啤酒
def初始化（啤酒）
如果啤酒>99
啤酒=99
elsif啤酒<1
啤酒=“零”
结束
@啤酒
结束
措辞明确
num_name={
90=>“九十”，80=>“八十”，70=>“七十”，60=>“六十”，
50=>“五十”，40=>“四十”，30=>“三十”，20=>“二十”，
19=>“十九”，18=>“十八”，17=>“十七”，16=>“十六”，
15=>“十五”，14=>“十四”，13=>“十三”，12=>“十二”，
11=>“十一”，10=>“十”，9=>“九”，8=>“八”，7=>“七”，
6=>“六”，5=>“五”，4=>“四”，3=>“三”，2=>“二”，1=>“一”
}
worded=“”
啤酒=@啤酒
斯普利特啤酒=啤酒到斯普利特
num_name.每个do|编号、名称|
拆分编号=编号到拆分编号
如果啤酒=数量
措辞为19&&split\u编号[0]。to\u i==split\u啤酒[0]。to\u i
措辞你的台词：

split_beers = beers.to_s.split
split_number = number.to_s.split

假设结果是一个数组，但事实并非如此，因为您没有提供一个用于拆分的模式
因此使用默认值。见：

最后是你想要的
 我现在更新了整个班级。抱歉，请在问题中说明。请阅读此处，了解对该问题的不同看法。具体而言，什么不起作用？我理解，但今后请尽最大努力在该问题中适当地间隔和缩进。通过使代码更易于阅读和理解，它使每个人的生活更轻松。看看@Jordan当前的编辑，看看如何最好地实现这一点。
puts "10".to_s.split.inspect        # gives ==> ["10"]
puts "10".to_s.split('',2).inspect  # gives ==> ["1", "0"]