Ruby 需要关于绑定对象的帮助吗

从

类绑定的对象将执行上下文封装在代码中的某个特定位置，并保留该上下文以备将来使用。变量、方法、self的值以及在此上下文中可以访问的迭代器块都被保留。可以使用Kernel#Binding创建绑定对象，并且可用于Kernel#set _trace_func的回调

---

有谁能帮我通过上面每一条粗体线的单个例子来理解这个事实吗？

方法：

x = eval("foo", binding) rescue "foo undefined"
puts x

def foo; "foo"; end

puts eval("foo", binding)

puts eval("self", binding)
class Foo
  def eval_self
    eval("self", binding)
  end
end
puts Foo.new.eval_self

block = eval("yield", binding) rescue "no iterator block"
puts block

def block
  eval("yield", binding)
end
puts block { "iterator block" }

class Test
  def test
    a = 1
  end
end

set_trace_func proc { |event, file, line, id, binding, classname|
  puts eval("self", binding)
}
t = Test.new
t.test

这将产生：

foo undefined
foo

main
#<Foo:0x10c5a3018>

no iterator block
iterator block

main
Test
#<Test:0x10204cb28>
#<Test:0x10204cb28>
Test
main
#<Test:0x10204cb28>
#<Test:0x10204cb28>
#<Test:0x10204cb28>
main
main
main

自身的值：

x = eval("foo", binding) rescue "foo undefined"
puts x

def foo; "foo"; end

puts eval("foo", binding)

puts eval("self", binding)
class Foo
  def eval_self
    eval("self", binding)
  end
end
puts Foo.new.eval_self

block = eval("yield", binding) rescue "no iterator block"
puts block

def block
  eval("yield", binding)
end
puts block { "iterator block" }

class Test
  def test
    a = 1
  end
end

set_trace_func proc { |event, file, line, id, binding, classname|
  puts eval("self", binding)
}
t = Test.new
t.test

这将产生：

foo undefined
foo

main
#<Foo:0x10c5a3018>

no iterator block
iterator block

main
Test
#<Test:0x10204cb28>
#<Test:0x10204cb28>
Test
main
#<Test:0x10204cb28>
#<Test:0x10204cb28>
#<Test:0x10204cb28>
main
main
main

这将产生：

foo undefined
foo

main
#<Foo:0x10c5a3018>

no iterator block
iterator block

main
Test
#<Test:0x10204cb28>
#<Test:0x10204cb28>
Test
main
#<Test:0x10204cb28>
#<Test:0x10204cb28>
#<Test:0x10204cb28>
main
main
main

内核#设置跟踪功能：

x = eval("foo", binding) rescue "foo undefined"
puts x

def foo; "foo"; end

puts eval("foo", binding)

puts eval("self", binding)
class Foo
  def eval_self
    eval("self", binding)
  end
end
puts Foo.new.eval_self

block = eval("yield", binding) rescue "no iterator block"
puts block

def block
  eval("yield", binding)
end
puts block { "iterator block" }

class Test
  def test
    a = 1
  end
end

set_trace_func proc { |event, file, line, id, binding, classname|
  puts eval("self", binding)
}
t = Test.new
t.test

这将产生：

foo undefined
foo

main
#<Foo:0x10c5a3018>

no iterator block
iterator block

main
Test
#<Test:0x10204cb28>
#<Test:0x10204cb28>
Test
main
#<Test:0x10204cb28>
#<Test:0x10204cb28>
#<Test:0x10204cb28>
main
main
main

main
试验
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#
试验
主要的
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#
#
主要的
主要的
主要的

---

您可以在its.

中阅读更多关于

内核#set_trace_func

的信息，这正是我搜索的内容。请用一些小例子来解释这一点

Kernel#set_trace_func.

。