Ruby 二维数组，如何创建修改原始数组的列数组

我有一个二维数组，我希望能够使用另一个数组，它引用原始数组的列。我可以用行来做，但我不知道如何用列来做

twodim = [[" "," "," "], [" "," "," "], [" "," "," "]]
row1 = twodim[0]
row1[0] = "X"

col1 = << twodim[0][0] << twodim[1][0] << twodim[2][0]
col1[2] = "X"

=> puts twodim
#actual result
=> [["X", " ", " "], [" ", " ", " "], [" ", " ", " "]]
#desired result
=> [["X", " ", " "], [" ", " ", " "], ["X", " ", " "]]

使用

说明：

$> col1[1].object_id
# => 2161281980 
$> col1[1] = "X"
# => "X" 
$> col1[1].object_id # Different object_id !!!
# => 2161469100
$> col1[1].replace("X")
# => "X" 
$> col1[1].object_id
# => 2161469100 # Same object_id !!!

在您的示例中，当执行

col1[2]=“X”

时，您正在为对象

col1[2]

分配一个值为

“X”

的新变量，这意味着

col1[2]

现在正在存储新对象的引用

“X”

。但是，在执行

col1[2].replace（“X”）

时，方法

replace

正在更改col1引用的对象的内容

以下示例将澄清上述解释：

$> col1[1].object_id
# => 2161281980 
$> col1[1] = "X"
# => "X" 
$> col1[1].object_id # Different object_id !!!
# => 2161469100
$> col1[1].replace("X")
# => "X" 
$> col1[1].object_id
# => 2161469100 # Same object_id !!!

---

我还建议你阅读这篇文章：

谢谢，这很有帮助。

$> col1[1].object_id
# => 2161281980 
$> col1[1] = "X"
# => "X" 
$> col1[1].object_id # Different object_id !!!
# => 2161469100
$> col1[1].replace("X")
# => "X" 
$> col1[1].object_id
# => 2161469100 # Same object_id !!!