简单的Ruby类混淆与调试

我正试图学习下面的ruby类，我只是不明白在调用新变量后的player函数时，输出语句的结果如何是“John Smith”

有没有更简单的方法？编码员的方式让我感到困惑 最后，您能告诉我如何在TextMate上调试Ruby类或任何Ruby代码吗？我的意思是调试就像调试VisualC++中显示的第一行得到调用和激励，然后跳到下一个…看看它是如何工作的

class Dungun
  attr_accessor :player 

def initialize(player_name)
  @player = Player.new(player_name)
  @rooms = []
end


class Player
  attr_accessor :name, :location
  def initialize(player_name)
    @name = player_name
  end
end

class Room
  attr_accessor :reference, :name, :description, :connection
  def initialize(reference,name,description,connection)
    @reference = reference
    @name = name
    @description = description
    @connection = connection

  end
end
end

my_dungun = Dungun.new("John Smith")
puts my_dungun.player.name

---

执行顺序

# 1. Called from my_dungun = Dungun.new("John Smith")
Dungun.new("John Smith")

# 2. Inside Dungun it will call the initialize from Dungun class
initialize("John Smith")

# 3. The initialize method, from Dungun class, will have this statement saying
# that instance variable @player will receive the
# result of Player.new("John Smith")
@player = Player.new("John Smith")

# 4. The Player's 'new' method will call the
# inner class Player's initialize method
initialize("John Smith")

# 5. The Player's initialize should assign "Jonh Smith" to @player's name
@name = "John Smith"

# 6. Then head back to where we stopped, and continue to the other
# statement at second line inside Dungun's 'new' method
@rooms = []

---

阅读ruby调试宝石和一些课程

你的代码也很混乱，为什么我要使用@player=player.new在这里面，会有更多的玩家需要添加。这不是代码。这是调用语句的顺序。我更新了我的答案，试图让它更适合您@user1556385