Rust 如何使用trait方法的默认实现而不是类型';什么是自定义实现?
有些trait方法有默认实现,可以被实现者覆盖。如何为覆盖默认值的结构使用默认实现 例如:Rust 如何使用trait方法的默认实现而不是类型';什么是自定义实现?,rust,traits,Rust,Traits,有些trait方法有默认实现,可以被实现者覆盖。如何为覆盖默认值的结构使用默认实现 例如: trait SomeTrait { fn get_num(&self) -> i32; fn add_to_num(&self) -> i32 { self.get_num() + 1 } } struct SomeStruct; impl SomeTrait for SomeStruct { fn get_num(&s
trait SomeTrait {
fn get_num(&self) -> i32;
fn add_to_num(&self) -> i32 {
self.get_num() + 1
}
}
struct SomeStruct;
impl SomeTrait for SomeStruct {
fn get_num(&self) -> i32 {
3
}
fn add_to_num(&self) -> i32 {
self.get_num() + 2
}
}
fn main() {
let the_struct = SomeStruct;
println!("{}", the_struct.add_to_num()); // how can I get this to print 4 instead of 5?
}
我提出的一个解决方案是定义一个虚拟结构,其中包含我想要更改的结构。然后,我可以选择哪些方法要覆盖,哪些方法要保留为默认方法 要扩展原始示例,请执行以下操作:
trait SomeTrait {
fn get_num(&self) -> i32;
fn add_to_num(&self) -> i32 {
self.get_num() + 1
}
}
struct SomeStruct;
impl SomeTrait for SomeStruct {
fn get_num(&self) -> i32 {
3
}
fn add_to_num(&self) -> i32 {
self.get_num() + 2
}
}
fn main() {
struct SomeOtherStruct {
base: SomeStruct,
}
impl SomeTrait for SomeOtherStruct {
fn get_num(&self) -> i32 {
self.base.get_num()
}
//This dummy struct keeps the default behavior of add_to_num()
}
let the_struct = SomeStruct;
println!("{}", the_struct.add_to_num());
//now we can call the default method using the original struct's data.
println!("{}", SomeOtherStruct { base: the_struct }.add_to_num());
}
如果
impl-Deref for SomeOtherStruct
whereDeref
,则可以调用“超类”方法,如some\u other\u struct.Deref().add\u to\u num()