Scala SLICK：如何在另一个查询中使用查询结果？

我想执行如下操作：

我想返回一个用户列表，首先按用户的“跟随者”排序，其次按一些额外的分数排序。 但是，我在下面编写的代码不起作用，因为资助者是被提升的滑头类型，因此在列表中找不到

        //The following represents the query for only funders who we are following
        val following_funders:  List[User]  = (
            for {
          funder <- all_funders
          f <- follows if f.followerId === id //get all the current users follower objects
          if f.followeeId === funder.id
        } yield funder
        ).list

      val all_funders_sorted = for {
        funder <- all_funders
        following_funder =  following_funders contains funder
      } yield (funder, following_funder)
      //sort the funders by whether or not they are following the funder and then map it to only the funders (i.e. remove the boolean)
      all_funders_sorted.sortBy(_._2.desc).sortBy(_._1.score.desc).map( x => x._1 )  

//下面的查询只针对我们关注的出资人
val下列出资人：列表[用户]=(
为了{
funder最终通过使用“inSet”找到了以下方法

        //The following represents the query for only funders who we are following
        val following_funders_ids:  List[Long]  = (
            for {
          funder <- all_funders
          f <- follows if f.followerId === id //get all the current users follower objects
          if f.followeeId === funder.id
        } yield funder.id
        ).list
      val all_funders_sorted = for {
        funder <- all_funders
        following_funder = funder.id inSet following_funders_ids
      } yield (funder, following_funder)
      //sort the funders by whether or not they are following the funder and then map it to only the funders (i.e. remove the boolean)
      all_funders_sorted.sortBy(_._2.desc).sortBy(_._1.impactPoints.desc).map( x => x._1 )  

//下面的查询只针对我们关注的出资人
val以下资金方ID:List[Long]=(
为了{
funder您需要在Slick中使用ID（即主键）。这就是在db端唯一标识对象的方式。您不需要执行第一个查询。您可以将其用作第二个查询的一个组件，而无需首先使用
中的
操作符执行它：

    //The following represents the query for only funders who we are following
    val following_funders_ids = (
        for {
      funder <- all_funders
      f <- follows if f.followerId === id //get all the current users follower objects
      if f.followeeId === funder.id
    } yield funder.id

  val all_funders_sorted = for {
    funder <- all_funders
    following_funder = funder.id in following_funders_ids
  } yield (funder, following_funder)
  //sort the funders by whether or not they are following the funder and then map it to only the funders (i.e. remove the boolean)
  all_funders_sorted.sortBy(_._1.impactPoints.desc).sortBy(_._2.desc).map( x => x._1 )   

scala> List( (1,"b"), (2,"a") ).sortBy(_._1).sortBy(_._2)
res0: List[(Int, String)] = List((2,a), (1,b))