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Scala+;Breeze-如何对索引元素进行操作?_Scala_Scala Breeze - Fatal编程技术网

Scala+;Breeze-如何对索引元素进行操作?

Scala+;Breeze-如何对索引元素进行操作?,scala,scala-breeze,Scala,Scala Breeze,我希望执行元素操作,如: matrixOne(指数):*=matrixTwo(指数) i、 e 矩阵酮(指数)=矩阵酮(指数):*matrixTwo(指数) 尽管我不相信语法是有效的,我也不认为有一种简单的方法可以做到这一点。有没有一种简单的方法不涉及元素上的循环 谢谢 但它确实有效 scala> val dm, dm2 = DenseMatrix.rand(3,3) dm: breeze.linalg.DenseMatrix[Double] = 0.28936576129658276

我希望执行元素操作,如:

matrixOne(指数):*=matrixTwo(指数)

i、 e

矩阵酮(指数)=矩阵酮(指数):*matrixTwo(指数)

尽管我不相信语法是有效的,我也不认为有一种简单的方法可以做到这一点。有没有一种简单的方法不涉及元素上的循环

谢谢

但它确实有效

scala> val dm, dm2 = DenseMatrix.rand(3,3)
dm: breeze.linalg.DenseMatrix[Double] =
0.28936576129658276  0.666815685335741   0.281387720258117
0.5738723072553482   0.7833150021047757  0.35576679755808027
0.9108889661007076   0.1477391442357301  0.15849984459500677
dm2: breeze.linalg.DenseMatrix[Double] =
0.431188741169817    0.5744275775115384  0.12976923536278662
0.08719379330185784  0.5968447834511466  0.15023676086236382
0.9136600875085321   0.9976862794513606  0.8561688429270904

scala> dm(IndexedSeq(0 -> 1, 1 -> 2)) += dm2(IndexedSeq(2 -> 1, 0 -> 0))
res4: breeze.linalg.Vector[Double] = breeze.linalg.SliceVector@3e6c9b94

scala> dm
res5: breeze.linalg.DenseMatrix[Double] =
0.28936576129658276  1.6645019647871016  0.281387720258117
0.5738723072553482   0.7833150021047757  0.7869555387278973
0.9108889661007076   0.1477391442357301  0.15849984459500677

scala> dm(IndexedSeq(0 -> 1, 1 -> 2)) :*= dm2(IndexedSeq(2 -> 1, 0 -> 0))
res6: breeze.linalg.Vector[Double] = breeze.linalg.SliceVector@6115d457

scala> dm
res7: breeze.linalg.DenseMatrix[Double] =
0.28936576129658276  1.660650772387923   0.281387720258117
0.5738723072553482   0.7833150021047757  0.33932636810069716
0.9108889661007076   0.1477391442357301  0.15849984459500677