Scala 按位右移，长不等于零？
我在REPL中玩，我看到了Scala 按位右移，长不等于零？,scala,Scala,我在REPL中玩，我看到了和>的这种行为。似乎一个Long应该占用64位，所以按64右移应该总是将数字置零 scala> 64 >> 64 res22: Int = 64 scala> 64 >> 65 res23: Int = 32 scala> 64 >> 66 res24: Int = 16 scala> 64 >> 67 res25: Int = 8 scala> 64 >> 68 res2
>64scala> 64 >> 64
res22: Int = 64
scala> 64 >> 65
res23: Int = 32
scala> 64 >> 66
res24: Int = 16
scala> 64 >> 67
res25: Int = 8
scala> 64 >> 68
res26: Int = 4
scala> 64 >> 69
res27: Int = 2
scala> 64 >> 70
res28: Int = 1
scala> 64 >> 71
res29: Int = 0
scala> 64 >>> 64
res30: Int = 64
scala> 64 >>> 65
res31: Int = 32
Scala中的这种行为是什么 Scala取右手并按左手操作数的字大小应用它。对于
Intscala> 64 >> 64
res0: Int = 64
scala> 64 >> 1
res1: Int = 32
scala> 64 >> 32
res2: Int = 64
scala> 8 >> 32
res3: Int = 8
scala> 8 >> 64
res4: Int = 8
scala> 8 >> 128
res5: Int = 8
scala> 64L >> 64
res6: Long = 64
scala> 64L >> 32
res7: Long = 0
Scala取右手并按左手操作数的字大小对其进行模化。对于
Intscala> 64 >> 64
res0: Int = 64
scala> 64 >> 1
res1: Int = 32
scala> 64 >> 32
res2: Int = 64
scala> 8 >> 32
res3: Int = 8
scala> 8 >> 64
res4: Int = 8
scala> 8 >> 128
res5: Int = 8
scala> 64L >> 64
res6: Long = 64
scala> 64L >> 32
res7: Long = 0
641000000scala> import java.lang.Long
import java.lang.Long
scala> Long.toBinaryString(64)
res139: String = 1000000
scala> Long.toBinaryString(64 >> 6 )
res140: String = 1
scala> Long.toBinaryString(64 >> 7 )
res141: String = 0
scala> 64 >> 64
res1: Int = 64
scala> 64 >> 32
res2: Int = 64
scala> 64 >> 128
res3: Int = 64
在
java.lang.Longscala.Long641000000scala> import java.lang.Long
import java.lang.Long
scala> Long.toBinaryString(64)
res139: String = 1000000
scala> Long.toBinaryString(64 >> 6 )
res140: String = 1
scala> Long.toBinaryString(64 >> 7 )
res141: String = 0
scala> 64 >> 64
res1: Int = 64
scala> 64 >> 32
res2: Int = 64
scala> 64 >> 128
res3: Int = 64
同样，在
java.lang.Longscala.LongLongIntscala>64l>>64l=64LongIntscala>64l>>64l=64