从AsyncOne-ScalaZ中提取值

我在ScalaZ和Scala都是新手，所以我面临以下问题。 我为我的应用程序编写了一些单元测试，我需要的是提取实际响应的值

你能告诉我怎么做吗

Expected :PaymentResponse(7bc2dc3b-c347-422f-b204-ccefb22708fa,
                          7bc2dc3b-c347-422f-b204-ccefb22708fa,USD,15.9,PAYMENT_PENDING,Paypal,VISA,None)
Actual   :\/-(EitherT(Future(Success(\/-(PaymentResponse(7bc2dc3b-c347-422f-b204-ccefb22708fa,
               7bc2dc3b-c347-422f-b204-ccefb22708fa,
               USD,15.9,PAYMENT_PENDING,Paypal,VISA,None))))))

整个测试：

"should return a payment object" in {
  val paymentId = UUID.randomUUID()
  val a: AsyncEither[FinanceGatewayError, PaymentResponse] = paymentService.getPayment(ProfileId("profileId"), paymentId.toString)

  val expectedPaymentResponse = PaymentResponse(
    paymentId = paymentId.toString,
    orderId = paymentId.toString,
    currency = "USD",
    amount = 15.90,
    status = PAYMENT_PENDING,
    paymentMethodLabel = "Paypal",
    paymentMethodIssuer = VISA,
    threeDSecure = None
  )
  \/-(paymentService.getPayment(ProfileId("profileId"), paymentId.toString)) shouldBe expectedPaymentResponse
}

---

最后，这是我的正确方法

"should return a payment object" in {
  val paymentId = UUID.randomUUID()
  val expectedPaymentResponse = PaymentResponse(
    paymentId = paymentId.toString,
    orderId = paymentId.toString,
    currency = "USD",
    amount = 15.90,
    status = PAYMENT_PENDING,
    paymentMethodLabel = "Paypal",
    paymentMethodIssuer = VISA,
    threeDSecure = None
  )
  val paymentResponse: AsyncEither[FinanceGatewayError, PaymentResponse] =
    paymentService.getPayment(ProfileId("profileId"), paymentId.toString)
  Await
    .result(paymentResponse.run, 5 seconds)
    .fold(
      error => fail(s"The test is failed because $error ."),
      payment => payment shouldBe expectedPaymentResponse
    )
}

---

你不能把你的预期反应包装成

\/-（EitherT（Future）（Success（\/-）（…）

？不，这不是一个选项。你能提供你的导入语句和类定义吗？我很难确定哪个库，例如，

或
来自哪个库。@Astrid你似乎不需要
val a=…
，因为它没有在任何地方使用。@Astrid我只是用我的实现添加了一个答案。仅供参考，我不需要它推荐使用
Await.result
，因为它会阻塞线程。Scalatest有几个选项用于处理
Future
s，这些选项可以并行运行-我在下面的回答中介绍了它们：。