Scheme 方案跟踪变量检查

Scheme 方案跟踪变量检查,scheme,racket,plai,Scheme,Racket,Plai,我需要函数来检查变量是否有阴影?函数应该返回#t或#f,这取决于是否有变量阴影。 我使用DrRacket实现代码()。到目前为止,我有这个 #lang plai (define-type WAE [num (n number?)] [add (lhs WAE?)(rhs WAE?)] [sub (lhs WAE?)(rhs WAE?)] [with (name symbol?)(named-expr WAE?)(body WAE?)] [id (name symbol?)]

我需要函数来检查变量是否有阴影?函数应该返回#t或#f,这取决于是否有变量阴影。 我使用DrRacket实现代码()。到目前为止,我有这个

#lang plai

(define-type WAE
  [num (n number?)]
  [add (lhs WAE?)(rhs WAE?)]
  [sub (lhs WAE?)(rhs WAE?)]
  [with (name symbol?)(named-expr WAE?)(body WAE?)]
  [id (name symbol?)])

(define (parse sexpr)
  (cond
    [(number? sexpr) (num sexpr)]
    [(symbol? sexpr) (id sexpr)]
    [(list? sexpr)
      (case (first sexpr)
        [(add) (add (parse (second sexpr)) (parse (third sexpr)))]
        [(sub) (sub (parse (second sexpr)) (parse (third sexpr)))]
        [(with) (with (first (second sexpr)) 
                      (parse (second (second sexpr)))
                      (parse(third sexpr)) )]]
     [else (error "unexpected token")]))

(define (symbol<? a b)
  (string<? (symbol->string a) (symbol->string b)))
我不知道
#lang plai
,但我相信代码的第二部分可能有语法错误

(define (shadowed? wae)
  (let 
   >>> Possible error >>> ([l(type-case WAE wae
      [num (n) n]
      [add (lft rght) (+ (shadowed-variable? lft) (shadowed-variable? rght))]
      [sub (lft rght) (- (shadowed-variable? lft) (shadowed-variable? rght))]
      [with (x i b) (shadowed-variable? (sub b x (shadowed-variable? i)))]
      [id (s) (error 'shadowed-variable? "free variable")])]) 
    >>>> Error >>> (if (remove-duplicates (flatten l) symbol=?) #t #f)))
试试这个,让我们知道

(define (shadowed? wae)
  (let 
    ([l (type-case WAE wae
      [num (n) n]
      [add (lft rght) (+ (shadowed-variable? lft) (shadowed-variable? rght))]
      [sub (lft rght) (- (shadowed-variable? lft) (shadowed-variable? rght))]
      [with (x i b) (shadowed-variable? (sub b x (shadowed-variable? i)))]
      [id (s) (error 'shadowed-variable? "free variable")])]) 
    (if (remove-duplicates (flatten l)) symbol=?) #t #f))

你能不能比“它不起作用”更具体一点?发生了什么不应该发生,或不应该发生但应该发生的事情?是的,可能是错误,但它仍然不能正常工作。例如,(带阴影的?(id'x))应该返回#t,(带阴影的?(num 1))应该返回#f。我到了这里error@vladang为什么
(隐藏的?(id'x))
应该是
#t
?您的
id
案例中是否有
error'阴影变量?“自由变量”)
。另外,请尝试REPL中的
(删除重复项(展平1)symbol=?)
,看看会发生什么。
(define (shadowed? wae)
  (let 
    ([l (type-case WAE wae
      [num (n) n]
      [add (lft rght) (+ (shadowed-variable? lft) (shadowed-variable? rght))]
      [sub (lft rght) (- (shadowed-variable? lft) (shadowed-variable? rght))]
      [with (x i b) (shadowed-variable? (sub b x (shadowed-variable? i)))]
      [id (s) (error 'shadowed-variable? "free variable")])]) 
    (if (remove-duplicates (flatten l)) symbol=?) #t #f))